如何从XML中的特定元素中查找列表符/属性？

Question

如何查询xml文档以返回特定元素的子元素/属性列表。

var entry = from item in doc.Descendants("GROUP")
                        where (string)item.Attribute("meetsMark") == "1"
                        select new
                        {                                
                            code = (string)item.Attribute("code"),                               
                        };

上面的代码仅返回属于元素GROUP的条目，其中MeetsMark属性为“ 1”。 对于它返回代码的每个元素，我还需要获取其中包含的每个Summary属性的'sum'和'number'列表。 示例：我需要查询返回：

代码=次要

总和= SUM1

数= 1

总和= SUM3

数= 3

总和= SUM4

数= 4

代码= THIRD

总和= SUM10

数= 1

总和= SUM30

数= 3

总和= SUM40

数= 4

下面是xml结构。

 <GROUP id="GRP2" code="MAIN" meetsMark="0" <GROUP id="GRP3" code="SECONDARY" meetsMark="1" <ITEMS> <ITEM id="ITM6" <SUMMARY sum="SUM1" number="1" </SUMMARY> </ITEM> <ITEM id="ITM14" <SUMMARY sum="SUM3" number="3" </SUMMARY> </ITEM> <ITEM id="ITM15" <SUMMARY sum="SUM4" number="4" </SUMMARY> </ITEM> </ITEMS> </GROUP> <GROUP id="GRP4" code="THIRD" meetsMark="1" <ITEMS> <ITEM id="ITM95" <SUMMARY sum="SUM10" number="1" </SUMMARY> </ITEM> <ITEM id="ITM96" <SUMMARY sum="SUM30" number="3" </SUMMARY> </ITEM> <ITEM id="ITM97" <SUMMARY sum="SUM40" number="4" </SUMMARY> </ITEM> </ITEMS> </GROUP> </GROUP> 

Answer 1

就像这样...（为清楚起见，省略了换行符）

var groups = from group in doc.Descendants("GROUP")
            where (string)group.Attribute("meetsMark") == "1"
            select group

var subgroups = from subgroup in groups.Descendants("GROUP")
           where subgroup.Attribute("code").Value == "SECONDARY"
           select subgroup;

foreach( var subgroup in subgroups )
{
   System.Console.WriteFormat( "code = {0}", subgroup.Attribute("code").Value );

   var sums = from summary in subgroup.Descendants("SUMMARY")

   foreach( var sum in sums )
   {
       System.Console.WriteFormat( "sum = {0}", subgroup.Attribute("sum").Value );
       System.Console.WriteFormat( "number = {0}", subgroup.Attribute("number").Value );
   }
}