分配变量时发生Python语法错误

Question

我是python的新手，我正在尝试分配变量，提示systax错误

protocol = input.readLine()
connectUrlHttp='http'
connectUrlHttps='https'


if protocol== "t3s":
 connectUrl=connectUrlHttps
elif protocol== "iiops":
  connectUrl=connectUrlHttps
else:
connectUrl=connectUrlHttp


  sca_deployComposite(connectUrl"://"+host+":"+port,emdroot+"/"+compositeLoc,owrite,user, password,default)

我面临以下错误

(no code object) at line 0
  File "/scratch/agentHome/sdappaji2/core/12.1.0.3.0/EMStage/PAF/DeployCompositesDP1367835748253/deploycompositesscripts/deployComposites.py", line 36
    connectUrl=connectUrlHttp

请指导我，并给我一些指导

Answer 1

在Python中， 缩进级别很重要：

每个缩进级别使用4个空格。

-PEP 8-Python代码样式指南

您的代码应该看起来像这样：

protocol = input.readLine()
connectUrlHttp = 'http'
connectUrlHttps = 'https'

if protocol == "t3s":
    connectUrl = connectUrlHttps
elif protocol == "iiops":
    connectUrl = connectUrlHttps
else:
    connectUrl = connectUrlHttp

# Note the `+` after `connectUrl` on the next line:
sca_deployComposite(connectUrl + "://" + host + ":" + port, emdroot + "/" +
                    compositeLoc, owrite, user, password, default)

Answer 2

实际的语法错误在这里：

sca_deployComposite(connectUrl"://"+host+":"+port,emdroot+"/"+compositeLoc,owrite,user, password,default)
                            ^^^

您可能错过了+ 。

正如Ashwini指出的那样，缩进在else后面也是错误的。

Answer 3

else:您的代码未正确缩进else:

if protocol== "t3s":
 connectUrl=connectUrlHttps
elif protocol== "iiops":
  connectUrl=connectUrlHttps
else:
    connectUrl=connectUrlHttp

sca_deployComposite(connectUrl+"://"+host+":"+port,emdroot+"/"+compositeLoc,owrite,user, password,default)

另外，您在sca_deployComposite(connectUrl之后，缺少了一个+ 。