Bash备份多个目录中的指定文件扩展名

Question

我在这里find "$directory" -name "*.sh" -print0 | xargs -0 cp -t ~/bckup find "$directory" -name "*.sh" -print0 | xargs -0 cp -t ~/bckup备份以.sh结尾的所有内容。 对于多个文件扩展名，我该怎么办？ 我尝试了引号，括号和$的不同组合。 他们都没有工作= \\

我也想将某些文件扩展名备份到不同的文件夹中，但不确定如何在文件名中搜索特定扩展名。

这是我的整个代码，以防万一：

#!/bin/bash


collect()
{
find "$directory" -name "*.(sh|c)" -print0 | xargs -0 cp -t ~/bckup #xargs handles files names with spaces. Also gives error of "cp: will not overwrite just-created" even if file didn't exist previously
}

echo "Starting log"

timelimit=10
echo "Please enter the directory that you would like to collect.
If no input in 10 secs, default of /home will be selected"

read -t $timelimit directory

if [ ! -z "$directory" ] #if directory doesn't have a length of 0
then
echo -e "\nYou want to copy $directory." #-e is so the \n will work and it won't show up as part of the string
else
directory=/home/
echo "Time's up. Backup will be in $directory"
fi

if [ ! -d ~/bckup ]
then
echo "Directory does not exist, creating now"
mkdir ~/bckup
fi 

collect
echo "Finished collecting"

exit 0

Answer 1

一种选择是使用内置逻辑或（从查找手册页）：

   expr1 -o expr2
          Or; expr2 is not evaluated if expr1 is true.

因此，您可以执行以下操作：

find "$directory" -name '*.c' -o -name '*.sh'