计算平均值并在python中进行比较

Question

我有一组值tgat表示平均一个后编码的人数。 这些是pcode1 = 239 ， pcode2 = 245 ， pcode3 = 210和pcode4 = 217现在是我所困的地方。 我假设平均值是allpcode = 220 。

有没有办法在python中编写代码，这样我就可以将每个单独的pcode与总平均值进行比较？ 我想要做的恰恰是说比较pcode1到allpcode如果pcode1高于/低于allpcode显示了从平均pcode1 ，说pcode1低于allpcode小于或更高allpcode 。 然后，我想对所有其他pcode重复：)

我想在屏幕上显示所有较低的平均值和较高的所有平均值。

因此，类似pcode 3和4的平均值低于所有pcode平均值，而pcode 1和2则高于所有p代码。

是否可以创建这样的代码，因为我不知道如何/从哪里开始？

Answer 1

在这种情况下，您经常要遍历一组值的所有位置，通常最好使用单个list ， dict或其他collection变量，而不是一堆单独的变量。 例如：

pcodes = {1: 239, 2: 245, 3: 210, 4: 217}

现在您可以编写如下代码：

pcodes = {1: 239, 2: 245, 3: 210, 4: 217}
allpcode = 220

for pcode, value in pcodes.items():
    if value < allpcode:
        print('code {} is lower than allpcode'.format(pcode))
    elif value > allpcode:
        print('code {} is higher than allpcode'.format(pcode))

---

如果您确实想拥有单独的变量，则必须做更多的工作，如下所示：

pcode1 = 239
pcode2 = 245
pcode3 = 210
pcode4 = 217
allpcode = 220

for i, value in enumerate((pcode1, pcode2, pcode3, pcode4)):
    if value < allpcode:
        print('code {} is lower than allpcode'.format(i + 1))
    elif value > allpcode:
        print('code {} is higher than allpcode'.format(i + 1))

Answer 2

如果只想匹配值，则可以使用列表：

>>> pcode1 = 239
>>> pcode2 = 245
>>> pcode3 = 210
>>> pcode4 = 217
>>> lis = [pcode1, pcode2, pcode3, pcode4]
>>> allpcode= 220

>>> for i,x in enumerate(lis):
    if x < allpcode:
        print "pcode{} is less than {}".format(i+1,allpcode)
    elif x > allpcode:    
        print "pcode{} is greater than {}".format(i+1,allpcode)
...         
pcode1 is greater than 220
pcode2 is greater than 220
pcode3 is less than 220
pcode4 is less than 220

更好地使用字典：

由于变量只是对python中值的引用，因此您无法访问变量名。 如果您有很多pcodes那么为每个pcodes定义一个变量是解决此问题的不好方法，那么使用dict会更干净。

#create dictionary with keys named pcode1, pcode2,...     
>>> dic = {'pcode1':239, 'pcode2':245, 'pcode3':210, 'pcode4':217}

>>> for k,v in dic.items():
    if v < allpcode:
        print "{} is less than {}".format(k ,'allpcode')
    elif v > allpcode:    
        print "{} is greater than {}".format(k,'allpcode')
...         
pcode3 is less than allpcode
pcode2 is greater than allpcode
pcode1 is greater than allpcode
pcode4 is less than allpcode

尽管字典不维护任何顺序，但您可能必须collections.OrderedDict或在此处sorted以sorted特定顺序获取键。