[英]Email multiple recipients Python
我正在尝试使用下面的pyton脚本通过电子邮件发送多个收件人。 我已经在论坛上搜索了答案,但是无法正确实现其中的任何一个。 如果有人有时间检查我的脚本并发现/解决问题,将不胜感激。
这是我的脚本,我收集的问题在“ sendmail”部分,但无法弄清楚如何解决:
gmail_user = "sender@email.com"
gmail_pwd = "sender_password"
recipients = ['recipient1@email.com','recipient2@email.com']
def mail(to, subject, text, attach):
msg = MIMEMultipart()
msg['From'] = gmail_user
msg['To'] = ", ".join(recipients)
msg['Subject'] = subject
msg.attach(MIMEText(text))
part = MIMEBase('application', 'octet-stream')
part.set_payload(open(attach, 'rb').read())
Encoders.encode_base64(part)
part.add_header('Content-Disposition',
'attachment; filename="%s"' % os.path.basename(attach))
msg.attach(part)
mailServer = smtplib.SMTP("smtp.gmail.com", 587)
mailServer.ehlo()
mailServer.starttls()
mailServer.ehlo()
mailServer.login(gmail_user, gmail_pwd)
mailServer.sendmail(gmail_user, to, msg.as_string())
mailServer.close()
mail("recipient1@email.com, recipient2@email.com",
"Subject",
"Message",
"attchachment")
任何见识将不胜感激。
最好,
马特
应该更像
mail(["recipient1@email.com", "recipient2@email.com"],
"Subject",
"Message",
"attchachment")
您已经声明了一个收件人数组,该收件人太全局了,您可以在不将其作为参数传递给mail
情况下使用它。
我写了这段代码来完成您想要的事情。 如果您发现错误,请通知我(我已经对其进行了测试并且可以正常工作):
import email as em
import smtplib as smtp
import os
ENDPOINTS = {KEY: 'value@domain.com'}
class BoxWriter(object):
def __init__(self):
pass
def dispatch(self, files, box_target, additional_targets=None, email_subject=None, body='New figures'):
"""
Send an email to multiple recipients
:param files: list of files to send--requires full path
:param box_target: Relevant entry ENDPOINTS dict
:param additional_targets: other addresses to send the same email
:param email_subject: optional title for email
"""
destination = ENDPOINTS.get(box_target, None)
if destination is None:
raise Exception('Target folder on Box does not exist')
recipients = [destination]
if additional_targets is not None:
recipients.extend(additional_targets)
subject = 'Updating files'
if email_subject is not None:
subject = email_subject
message = em.MIMEMultipart.MIMEMultipart()
message['From'] = 'user@domain.com'
message['To'] = ', '.join(recipients)
message['Date'] = em.Utils.formatdate(localtime=True)
message['Subject'] = subject
message.attach(em.MIMEText.MIMEText(body + '\n' +'Contents: \n{0}'.format('\n'.join(files))))
for f in files:
base = em.MIMEBase.MIMEBase('application', "octet-stream")
base.set_payload(open(f, 'rb').read())
em.Encoders.encode_base64(base)
base.add_header('Content-Disposition', 'attachment; filename={0}'.format(os.path.basename(f)))
message.attach(base)
conn = smtp.SMTP('smtp.gmail.com', 587)
un = 'user@gmail.com'
pw = 'test1234'
conn.starttls()
conn.login(un, pw)
conn.sendmail('user@domain.com', recipients, message.as_string())
conn.close()
我遇到了同样的问题,我现在解决了这个问题。 这是我的代码-
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
import smtplib
import datetime
def sendMail():
message = MIMEMultipart()
message["To"] = "xxxxx@xxxx.com,yyyy@yyyy.com"
message["Cc"] = "zzzzzz@gmail.com,*********@gmail.com"
message["From"] = "xxxxxxxx@gmail.com"
message["Password"] = "***************"
server = 'smtp.gmail.com:587'
try:
now = datetime.datetime.now()
message['Subject'] = "cxxdRL Table status (Super Important Message) - "+str(now)
server = smtplib.SMTP(server)
server.ehlo()
server.starttls()
server.login(message["From"], message["Password"])
server.sendmail(message["From"], message["To"].split(",") + message["Cc"].split(","), message.as_string())
server.quit()
print('Mail sent')
except:
print('Something went wrong...')
sendMail()
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