[英]Regex: extract float data from String and group it
我有一个像这样的字符串:
288.999,224.004 283.665,258.338 313.332,293.005 312.332,336.671 270.999,389.338 371.998,412.338
我尝试将数据解析为浮点值,但我想对它进行排序! 逗号前的值应为我的x值,逗号后的值应为y值。
Pattern p = Pattern.compile("[0-9]+.[0-9]*");
Matcher m = p.matcher(pointString);
while(m.find())
{
System.out.print("x:"+m.group(0)); //x- Values
// System.out.print("y:"+m.group(1)); //y- Values
}
这段代码只创建了一个组...我应该如何更改我的String模式以使用y-Values获得第二个组...
首选结果:
x:288.999
y:224.004
x:283.665
y:258.338
....
保持简单, 分割就足够了:
String input = "288.999,224.004 283.665,258.338 313.332,293.005 312.332,336.671 270.999,389.338 371.998,412.338";
String[] points = input.split(" ");
for (String point : points) {
String[] coordinates = point.split(",");
System.out.println("x:" + coordinates[0]);
System.out.println("y:" + coordinates[1]);
}
您正在寻找的模式:
((?:\\d*\\.\\d+)|(?:\\d+\\.\\d*)) *, *((?:\\d*\\.\\d+)|(?:\\d+\\.\\d*))
同样,group(0)将带来整个比赛,您宁愿在寻找group(1)和group(2)
这会起作用
String str = "288.999,224.004 283.665,258.338 313.332,293.005 312.332,336.671 270.999,389.338 371.998,412.338";
String[] points=str.split(" ");
String[] point=new String[2];
for(int i=0;i<points.length;i++){
point=points[i].split(",");
System.out.println("X-val: "+point[0]);
System.out.println("Y-val: "+point[1]);
}
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