[英]How can i update the Records included in another query using SUM and GROUP By in mysql
[英]mysql - check if a group of elements are included in another group
我有以下设置:
像这样的PHP数组:
$arr = array(1, 2, 3, 4);
一个如下所示的查询:
SELECT `epicThing` FROM `epicTable` AS `epic`
WHERE
SELECT `ids` FROM `someTable`
WHERE `epic`.`somethingSomething` = `someTable`.`somethingElse`
(<<<< HERE IS MY PROBLEM >>>>)
子查询返回类似(1,2,3,4,5,6,7,8,9)的内容。
现在我需要检查的是数组中的每个元素都在子查询的返回答案中。
基本上就像是
SELECT `epicThing` FROM `epicTable` AS `epic`
WHERE
'1' IN (
SELECT `ids` FROM `someTable`
WHERE `epic`.`somethingSomething` = `someTable`.`somethingElse`
)
AND
'2' IN (
SELECT `ids` FROM `someTable`
WHERE `epic`.`somethingSomething` = `someTable`.`somethingElse`
)
AND
'3' IN (
SELECT `ids` FROM `someTable`
WHERE `epic`.`somethingSomething` = `someTable`.`somethingElse`
).......
但对于每个元素。
为简单起见,我们假设元素总是按顺序排列(因为我可能需要将数组转换为字符串),否则就不可能。 但如果可以的话,我更喜欢一般的解决方案。
我不想做的是在php中获取数据并在那里检查(这只是一个非常小的一个巨大的查询部分)。
如果我正确理解您的问题,我认为这将是您测试数组中所有ID与数据库中记录匹配的最简单方法:
<?php
$myArray = array(1,2,3);
$myArrayCount = count($myArray);
// Convert array for the query
$queryArray = implode(",", $myArray);
SELECT COUNT(DISTINCT(YourTable.id)) AS count
FROM YourTable
WHERE YourTable.id IN ($queryArray)
HAVING count = $myArrayCount;
?>
如果HAVING count = $ myArrayCount, Mysql将返回空结果; 与您要检查的ID数量不匹配。
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