[英]Opening 2 data files with C++
我编写了一个程序,根据从输入文件中读取的数据创建gnuplot命令。 我需要太多命令才能手动执行此操作。 这工作得很好,但是我现在需要从两个不同的数据文件中读取数据,并使用它们来创建gnuplot命令。 不幸的是,现在两个文件的读取似乎出了问题。 读取数据文件涉及的部分代码如下:
#include <iostream>
#include <fstream>
#include <sstream>
using namespace std;
int n_snapshots;
int main () {
std::cout << "Enter number of snapshots" << "\n";
std::cin >> n_snapshots;
int snap_cell_count[n_snapshots];
std::ifstream in_file_count("data/snapshot_data");
std::ifstream in_file_fates("data/cell_fates_data_final");
for (int i=0; i<n_snapshots; i++) {
in_file_count >> snap_cell_count[i];
}
in_file_count.close();
int cell_fates[snap_cell_count[n_snapshots-1]];
for (int i=0; i<snap_cell_count[n_snapshots-1]; i++) {
in_file_fates >> cell_fates[i];
}
in_file_fates.close();
n_snapshots只是一个整数,snap_cell_count []是一个包含“ n_shapshots”元素的数组,每个元素都从数据文件“ snapshot_data”中读取一个值。 cell_fates []是一个数组,其元素数等于snap_cell_count []中的最后一个元素的值,并且再次从文件(在这种情况下为“ cell_fates_data_final”)中读取其元素的值。 要读取的数据文件存储在名为“ data”的文件夹中。
不幸的是,编译器返回以下错误。
Undefined symbols for architecture x86_64:
"std::basic_string<char, std::char_traits<char>, std::allocator<char> >::c_str() const", referenced from:
_main in ccrpSAv5.o
"std::basic_stringstream<char, std::char_traits<char>, std::allocator<char> >::str() const", referenced from:
_main in ccrpSAv5.o
"std::basic_istream<char, std::char_traits<char> >::operator>>(int&)", referenced from:
_main in ccrpSAv5.o
"std::basic_ostream<char, std::char_traits<char> >::operator<<(int)", referenced from:
_main in ccrpSAv5.o
"std::basic_string<char, std::char_traits<char>, std::allocator<char> >::~basic_string()", referenced from:
_main in ccrpSAv5.o
"std::basic_ifstream<char, std::char_traits<char> >::close()", referenced from:
_main in ccrpSAv5.o
"std::basic_ifstream<char, std::char_traits<char> >::basic_ifstream(char const*, std::_Ios_Openmode)", referenced from:
_main in ccrpSAv5.o
"std::basic_ifstream<char, std::char_traits<char> >::~basic_ifstream()", referenced from:
_main in ccrpSAv5.o
"std::basic_ofstream<char, std::char_traits<char> >::open(char const*, std::_Ios_Openmode)", referenced from:
_main in ccrpSAv5.o
"std::basic_ofstream<char, std::char_traits<char> >::close()", referenced from:
_main in ccrpSAv5.o
"std::basic_ofstream<char, std::char_traits<char> >::basic_ofstream()", referenced from:
_main in ccrpSAv5.o
"std::basic_ofstream<char, std::char_traits<char> >::~basic_ofstream()", referenced from:
_main in ccrpSAv5.o
"std::basic_stringstream<char, std::char_traits<char>, std::allocator<char> >::basic_stringstream(std::_Ios_Openmode)", referenced from:
_main in ccrpSAv5.o
"std::basic_stringstream<char, std::char_traits<char>, std::allocator<char> >::~basic_stringstream()", referenced from:
_main in ccrpSAv5.o
"std::ios_base::Init::Init()", referenced from:
__static_initialization_and_destruction_0(int, int) in ccrpSAv5.o
"std::ios_base::Init::~Init()", referenced from:
__static_initialization_and_destruction_0(int, int) in ccrpSAv5.o
"std::cin", referenced from:
_main in ccrpSAv5.o
"std::cout", referenced from:
_main in ccrpSAv5.o
"std::basic_ostream<char, std::char_traits<char> >& std::operator<< <std::char_traits<char> >(std::basic_ostream<char, std::char_traits<char> >&, char const*)", referenced from:
_main in ccrpSAv5.o
"___gxx_personality_v0", referenced from:
Dwarf Exception Unwind Info (__eh_frame) in ccrpSAv5.o
ld: symbol(s) not found for architecture x86_64
collect2: error: ld returned 1 exit status
这是使用Mac OSX Mountain Lion上的gcc编译器进行编译的。
有人知道这是怎么回事吗?
好吧,对于初学者来说,您不能只说int snap_cell_count[n_snapshots]
,而n_snapshots
的值是在运行时确定的。 你必须做类似的事情
int *snap_cell_count = new int[n_snapshots];
// do some stuff
delete[] snap_cell_count;
cell_fates
至于您的链接器错误,也许这个问题可以解决您的问题...
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