如何在python中使用cgi.parse_qs列出数组？

Question

import cgi

data = 'next=/contact/200/106260296&next=/contact/200/106260296&next=/contact/200/106260296&next=/contact/200/106260296&'

x = cgi.parse_qs(data)

next_list = x['next']

我对如何使用x或类似的y来获取所有“下一个”感到困惑。

有任何想法吗？

Answer 1

import cgi

data = 'next=/contact/200/106260296&next=/contact/200/106260296&next=/contact/200/106260296&next=/contact/200/106260296&'

x = cgi.parse_qs(data)

next_list = x['next']

for i in range(len(x['next'])) :
    print x['next'][i]

Answer 2

除了导入其他库，您还可以使用普通的旧列表切片：

data = 'next=/contact/200/106260296&next=/contact/200/106260296&next=/contact/200/106260296&next=/contact/200/106260296&'

next_list = [x[:-1] for x in data.split('next=')[1:]]

现在next_list看起来像这样： ['/contact/200/106260296', '/contact/200/106260296', '/contact/200/106260296', '/contact/200/106260296'] 。

Answer 3

my_list = [j.split('/')[1:] for j in
           [e.split('/contact')[1] for e in cgi.parse_qs(data)['next']]
          ]

然后，您可以执行以下操作：

for x, y in my_list:
    print x, y

输出：

200 106260296
200 106260296
200 106260296
200 106260296