[英]PHP date add 5 year to current date
我有这个 PHP 代码:
$end=date('Y-m-d');
我用它来获取当前日期,我需要未来 5 年的日期,例如:
$end=date('(Y + 5)-m-d');
我怎样才能做到这一点?
尝试:
$end = date('Y-m-d', strtotime('+5 years'));
根据这篇文章修改日期
strtotime() 非常强大,并且允许您使用它的相对表达式轻松修改/转换日期:
程序性的
$dateString = '2011-05-01 09:22:34';
$t = strtotime($dateString);
$t2 = strtotime('-3 days', $t);
echo date('r', $t2) . PHP_EOL; // returns: Thu, 28 Apr 2011 09:22:34 +0100
日期时间
$dateString = '2011-05-01 09:22:34';
$dt = new DateTime($dateString);
$dt->modify('-3 days');
echo $dt->format('r') . PHP_EOL; // returns: Thu, 28 Apr 2011 09:22:34 +0100
您可以在 strtotime() 中抛出的内容非常令人惊讶并且非常易于阅读。 看看这个例子,寻找下周的星期二。
程序性的
$t = strtotime("Tuesday next week");
echo date('r', $t) . PHP_EOL; // returns: Tue, 10 May 2011 00:00:00 +0100
日期时间
$dt = new DateTime("Tuesday next week");
echo $dt->format('r') . PHP_EOL; // returns: Tue, 10 May 2011 00:00:00 +0100
请注意,上面的这些示例是相对于现在的时间返回的。 strtotime() 和 DateTime 构造函数采用的时间格式的完整列表列在PHP 支持的日期和时间格式页面上。
另一个适合您情况的示例可能是: 基于这篇文章
<?php
//How to get the day 3 days from now:
$today = date("j");
$thisMonth = date("n");
$thisYear = date("Y");
echo date("F j Y", mktime(0,0,0, $thisMonth, $today+3, $thisYear));
//1 week from now:
list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
echo date("F j Y", mktime(0,0,0, $thisMonth, $today+7, $thisYear));
//4 months from now:
list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
echo date("F j Y", mktime(0,0,0, $thisMonth+4, $today, $thisYear));
//3 years, 2 months and 35 days from now:
list($today,$thisMonth,$thisYear) = explode(" ", date("j n Y"));
echo date("F j Y", mktime(0,0,0, $thisMonth+2, $today+35, $thisYear+3));
?>
使用此代码将年、月、日、小时、分钟或秒添加到给定日期
echo date("Y-m-d H:i:s", strtotime("+1 years", strtotime('2014-05-22 10:35:10'))); //2015-05-22 10:35:10
echo date("Y-m-d H:i:s", strtotime("+1 months", strtotime('2014-05-22 10:35:10')));//2014-06-22 10:35:10
echo date("Y-m-d H:i:s", strtotime("+1 days", strtotime('2014-05-22 10:35:10')));//2014-05-23 10:35:10
echo date("Y-m-d H:i:s", strtotime("+1 hours", strtotime('2014-05-22 10:35:10')));//2014-05-22 11:35:10
echo date("Y-m-d H:i:s", strtotime("+1 minutes", strtotime('2014-05-22 10:35:10')));//2014-05-22 10:36:10
echo date("Y-m-d H:i:s", strtotime("+1 seconds", strtotime('2014-05-22 10:35:10')));//2014-05-22 10:35:11
您还可以减去替换 + 到 -
$date = strtotime($row['timestamp']);
$newdate = date('d-m-Y',strtotime("+1 year",$date));
使用碳非常容易。 $date = "2016-02-16"; // Or Your date $newDate = Carbon::createFromFormat('Ym-d', $date)->addYear(1);
使用碳:
$dt = Carbon::now();
echo $dt->addYears(5);
要将一年添加到今天的日期,请使用以下命令:
$oneYearOn = date('Y-m-d',strtotime(date("Y-m-d", mktime()) . " + 365 day"));
您可以为此目的使用 DateInterval;
$currentDate = new \DateTime(); //creates today timestamp
$currentDate->add(new \DateInterval('P5Y')); //this means 5 Years
and you can now format it;
$currentDate->format('Y-m-d');
试试这个,
$presentyear = '2013-08-16 12:00:00';
$nextyear = date("M d,Y",mktime(0, 0, 0, date("m",strtotime($presentyear )), date("d",strtotime($presentyear )), date("Y",strtotime($presentyear ))+5));
echo $nextyear;
试试这个:
$yearnow= date("Y");
$yearnext=$yearnow+1;
echo date("Y")."-".$yearnext;
试试这个代码并添加接下来的天、月和年
// current month: Aug 2018
$n = 2;
for ($i = 0; $i <= $n; $i++){
$d = strtotime("$i days");
$x = strtotime("$i month");
$y = strtotime("$i year");
echo "Dates : ".$dates = date('d M Y', "+$d days");
echo "<br>";
echo "Months : ".$months = date('M Y', "+$x months");
echo '<br>';
echo "Years : ".$years = date('Y', "+$y years");
echo '<br>';
}
<?php
$current_date=strtotime(date('Ym-d'));
echo $end = date('Ym-d', strtotime('+5 years',$current_date));
?>
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