[英]R reshape wide data to long
我有以下数据框,它对跨列排列的多个条件给出了逻辑响应:
structure(list(Householdref = c("003015002024001", "003016003006001",
"003016004013001", "003016006002001", "003017003009002", "003017003009003",
"003017003009004", "003017003037001", "003017003049001", "003070001026001",
"003070003042001", "003070005002001", "003070005021001", "003070009005001",
"003071002055001", "003071003037001", "003072003029001", "003072006002001",
"003072006018001"), B5_Glass = c(FALSE, FALSE, FALSE, FALSE,
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE,
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE), B5_Glass.bottles = c(TRUE,
TRUE, FALSE, FALSE, TRUE, TRUE, FALSE, TRUE, FALSE, FALSE, TRUE,
TRUE, FALSE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE), B5_Paper.cardboard = c(FALSE,
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE,
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE
), B5_Metal.cans = c(TRUE, FALSE, FALSE, FALSE, TRUE, FALSE,
FALSE, FALSE, TRUE, TRUE, TRUE, TRUE, FALSE, FALSE, TRUE, TRUE,
TRUE, TRUE, TRUE), B5_Food.biodegradables = c(FALSE, FALSE, FALSE,
TRUE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE,
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE), B5_Plastic.polybags = c(TRUE,
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE,
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE
), B5_Plastic.bottles.containers = c(FALSE, FALSE, FALSE, FALSE,
FALSE, FALSE, TRUE, FALSE, TRUE, TRUE, FALSE, FALSE, TRUE, FALSE,
FALSE, TRUE, FALSE, FALSE, FALSE), B5_other = c(FALSE, FALSE,
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE,
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE)), .Names = c("Householdref",
"B5_Glass", "B5_Glass.bottles", "B5_Paper.cardboard", "B5_Metal.cans",
"B5_Food.biodegradables", "B5_Plastic.polybags", "B5_Plastic.bottles.containers",
"B5_other"), row.names = c("13", "21", "25", "29", "55", "56",
"57", "60", "61", "69", "76", "81", "83", "90", "101", "108",
"120", "125", "127"), class = "data.frame")
我需要重塑该数据,以便只有三列: Householdref, TRUE and FALSE
以便列名现在出现在TRUE或FALSE列中,以便每个Householdref
都有多个行。
我一直在尝试reshape()
,如下所示:
reshape(ar_waste_sep, direction="long", varying=2:9, sep=c("_"))
但最终结果是:
Householdref time B5 id
1.Glass 003015002024001 Glass FALSE 1
2.Glass 003016003006001 Glass FALSE 2
3.Glass 003016004013001 Glass FALSE 3
4.Glass 003016006002001 Glass FALSE 4
5.Glass 003017003009002 Glass FALSE 5
6.Glass 003017003009003 Glass FALSE 6
7.Glass 003017003009004 Glass FALSE 7
8.Glass 003017003037001 Glass FALSE 8
9.Glass 003017003049001 Glass FALSE 9
10.Glass 003070001026001 Glass FALSE 10
11.Glass 003070003042001 Glass FALSE 11
12.Glass 003070005002001 Glass FALSE 12
因此,正如您所看到的,我不太满意。 我在高低处搜索了一个示例,该示例将向我展示如何做我想做的事情,并确保它并不过分复杂,只是绕圈而行。 有人会知道一种快速简便的方法来实现我想要的吗,即:
Householdref TRUE FALSE
003015002024001 Glass NA
003015002024001 Glass.bottles NA
003015002024001 NA Paper.cardboard
003015002024001 NA Metal.cans
003015002024001 NA Plastic.bottles
003015002024001 NA Plastic
003017003009004 GLass NA
003017003009004 NA Glass.bottles
003017003009004 Paper.cardboardNA
提前致谢,
马蒂
您可以使用“ reshape2”中的melt
和dcast
获得(我认为)您想要的:
library(reshape2)
mydf <- melt(ar_waste_sep, id.vars="Householdref")
head(mydf)
# Householdref variable value
# 1 003015002024001 B5_Glass FALSE
# 2 003016003006001 B5_Glass FALSE
# 3 003016004013001 B5_Glass FALSE
# 4 003016006002001 B5_Glass FALSE
# 5 003017003009002 B5_Glass FALSE
# 6 003017003009003 B5_Glass FALSE
out <- dcast(mydf, Householdref + variable ~ value, value.var="variable")
head(out)
# Householdref variable FALSE TRUE
# 1 003015002024001 B5_Glass B5_Glass <NA>
# 2 003015002024001 B5_Glass.bottles <NA> B5_Glass.bottles
# 3 003015002024001 B5_Paper.cardboard B5_Paper.cardboard <NA>
# 4 003015002024001 B5_Metal.cans <NA> B5_Metal.cans
# 5 003015002024001 B5_Food.biodegradables B5_Food.biodegradables <NA>
# 6 003015002024001 B5_Plastic.polybags <NA> B5_Plastic.polybags
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