在Django json响应中添加外键引用

Question

在附加结果（附加外键）期间导致键错误

models.py

class table1
    id = models.IntegerField( primary key=TRUE)
    ref = models.ForeignKey('table2')

class table2
    name = models.CharField()
    id = models.IntegerField(primaryKey= True)
    address = models.CharField()

views.py

def relation(request)
"""
    some stuff
"""
    query = "query set makes object of table 1"

    result['content'].append([query['ref__address'])

错误是

Keyerror at /url
ref__address

Answer 1

def relation(request, pk):
    item = get_object_or_404(Table1, pk=pk)
    context= {'content': item}
    return render(request, 'table1/relation.html', context)

urlpatterns = patterns('',
    url(r'^table1/(?P<pk>\d+)/$', relation, name='relation'),
)

您的问题似乎是您的python均无效。