[英]SocketServer Python
因此,我发现了以下示例代码,该示例代码允许在给定的URL和端口处建立基本的python HTTP服务器。 我对Web服务器缺乏经验,并且正在尝试为此服务器的某些GET请求创建处理程序。 但是,当远程访问此URL时,我无法弄清楚如何为另一台计算机发出的GET请求创建处理程序。 有什么建议么?
import SocketServer
class MyTCPHandler(SocketServer.BaseRequestHandler):
"""
The RequestHandler class for our server.
It is instantiated once per connection to the server, and must
override the handle() method to implement communication to the
client.
"""
def handle(self):
# self.request is the TCP socket connected to the client
self.data = self.request.recv(1024).strip()
print "{} wrote:".format(self.client_address[0])
print self.data
# just send back the same data, but upper-cased
self.request.sendall(self.data.upper())
if __name__ == "__main__":
HOST, PORT = "url" , PORT
# Create the server, binding to localhost on port 9999
server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler)
# Activate the server; this will keep running until you
# interrupt the program with Ctrl-C
server.serve_forever()
这是一个如何工作的非常简单的示例。 您可以以此启动并调用它,例如:
curl -i 'http://localhost:5001/foo/bar?foo=bar' -X POST -d '{"Foo":"Bar"}'
HTTP/1.1 200 OK
Some response%
它缺少吨的东西,但至少应该给你某种想法。
import SocketServer
class MyTCPHandler(SocketServer.BaseRequestHandler):
def handle(self):
self.data = self.request.recv(1024).strip()
print self.data
self.parse_request(self.data)
func, args = self.path.split("/", 1)
args = args.split("/")
resp = getattr(self, func)(*args)
self.request.sendall("HTTP/1.1 200 OK\n")
self.request.sendall("\n")
self.request.sendall(resp)
def parse_request(self, req):
headers = {}
lines = req.splitlines()
inbody = False
body = ''
for line in lines[1:]:
if line.strip() == "":
inbody = True
if inbody:
body += line
else:
k, v = line.split(":", 1)
headers[k.strip()] = v.strip()
method, path, _ = lines[0].split()
self.path = path.lstrip("/")
self.method = method
self.headers = headers
self.body = body
self.path, self.query_string = self.path.split("?")
def foo(self, *args):
print self.path
print self.query_string
print self.body
print self.headers
print self.method
return "Some response"
if __name__ == "__main__":
server = SocketServer.TCPServer(("localhost", 5001), MyTCPHandler)
server.serve_forever()
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