如何在python 3.3中修复此错误？ TypeError：不可排序的类型：str（）<int（）

Question

我试图创建一个猜数字游戏，但收到“ guessestaken”错误，我从http://inventwithpython.com/IYOCGwP_book1.pdf第57页复制了代码。对不起，我对python有点陌生。

import random
guessestaken=0
print ("hello what ur name?")
myname=input()
number=random.randint(1,20)
print ("well " + myname + " i am thinking of a number guess it")

while guessestaken < 6 :
    guessestaken=guessestaken+1
    guess =input('take a guess')
    guess = int(guess)

    if guess <number:
        print('too low')
    if guess >number:
        print ('too high')
    if guess ==number:
        break
    if guess ==number:
        guessestaken=str(guessestaken)
        print ('good job ' + myname + ' you are right!')
        print ('you guessed it in ' + guessestaken + ' guesses')
    if guess !=number:
        guessestaken = str(guessestaken)
        print ("I am sorry but you couldn't get it right")
        print ("you couldn't guess it in " + guessestaken + " guesses")

Answer 1

错误消息是（试图）通知您您正在尝试将str与int进行比较。 特别是，应该有一个回溯通知您错误发生的位置：

Traceback (most recent call last):
  File "./tmp.py", line 8, in <module>
    while guessestaken < 6 :

您会看到您将guessestaken字符串显式转换为字符串：

guessestaken = str(guessestaken)

显然没有必要。 当您要打印猜测的数量时，可以使用+内联（不建议使用它或“ pythonic”）或使用format ：

print('you guessed it in ' + str(guessestaken) + ' guesses')
print('You guessed it in {} guesses'.format(guessestaken))

Answer 2

您正在将guesstaken转换为字符串以显示它

guessestaken=str(guessestaken)

然后while循环检查是否

while guessestaken < 6 :

这会导致类型错误（python无法比较string和int ）。 您应该简单地使用其他名称作为字符串，或者使用类似python的结构内联

print('You guessed it in {} guesses'.format(guessestaken))