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[英]Oracle: Comparing string columns from two different table without a primary key to find match/unmatched string
[英]Match the words in two columns oracle sql by breaking the string and comparing each word
我的表中有两列,例如column_A
和column_B
假设column_A
有数据“best buy card credit”, column_B
有“credit no take buy order”,这里我需要匹配两列中的单词并返回匹配单词的数量。 在这种情况下,它应该返回 2 作为“购买”和“信用”匹配。 任何人都可以建议 sql 代码来做同样的事情。
请注意: column_a
和column_b
大小不是固定的,即两者中的字数可能会改变。
with t as (
SELECT 1 AS ID, 'best buy card credit' column_1,
'credit no take buy order' column_2
FROM DUAL
UNION ALL
SELECT 2 AS ID, 'gaurav is fool' column_1, 'saurabh is fool' column_2
FROM DUAL
)
,t1_column1 as (
SELECT ID, LEVEL AS n, REGEXP_SUBSTR (column_1, '[^ ]+', 1, LEVEL) AS val
FROM t
CONNECT BY REGEXP_SUBSTR (column_1, '[^ ]+', 1, LEVEL) IS NOT NULL
)
,t1_column2 as (
SELECT ID, LEVEL AS n, REGEXP_SUBSTR (column_2, '[^ ]+', 1, LEVEL) AS val
FROM t
CONNECT BY REGEXP_SUBSTR (column_2, '[^ ]+', 1, LEVEL) IS NOT NULL
)
select id, LISTAGG(VAL,',') WITHIN GROUP(ORDER BY VAL ) words ,COUNT(*) "total matched words"
from
(
SELECT DISTINCT t1_column1.ID ID, t1_column1.val val
FROM t1_column1, t1_column2
WHERE t1_column1.ID = t1_column2.ID
AND t1_column1.val = t1_column2.val
)
group by id
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