I have two columns in my table for instance column_A
and column_B
Suppose column_A
has data "best buy card credit" and column_B
has "credit no take buy order", here i need to match the words in both the columns and return the number of matching words . In this case it should return 2 as "buy" and "credit" match. Can anyone please suggest sql code to do the same.
Please NOTE : size of column_a
and column_b
is not fixed ie the number of words in both might change.
with t as (
SELECT 1 AS ID, 'best buy card credit' column_1,
'credit no take buy order' column_2
FROM DUAL
UNION ALL
SELECT 2 AS ID, 'gaurav is fool' column_1, 'saurabh is fool' column_2
FROM DUAL
)
,t1_column1 as (
SELECT ID, LEVEL AS n, REGEXP_SUBSTR (column_1, '[^ ]+', 1, LEVEL) AS val
FROM t
CONNECT BY REGEXP_SUBSTR (column_1, '[^ ]+', 1, LEVEL) IS NOT NULL
)
,t1_column2 as (
SELECT ID, LEVEL AS n, REGEXP_SUBSTR (column_2, '[^ ]+', 1, LEVEL) AS val
FROM t
CONNECT BY REGEXP_SUBSTR (column_2, '[^ ]+', 1, LEVEL) IS NOT NULL
)
select id, LISTAGG(VAL,',') WITHIN GROUP(ORDER BY VAL ) words ,COUNT(*) "total matched words"
from
(
SELECT DISTINCT t1_column1.ID ID, t1_column1.val val
FROM t1_column1, t1_column2
WHERE t1_column1.ID = t1_column2.ID
AND t1_column1.val = t1_column2.val
)
group by id
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