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[英]SQL Select from 2 tables with same column names only return column when not null
[英]SQL select from 3 tables and merge column names
我正在尝试从MySQL的3个表中获取数据并更改/合并它们的列名。 现在,当我使用AS
设置列名称时,它们会重复出现。
人表:
id applicant_id employee_id
---------------------------------
1 3 6
2 4 10
3 12 30
申请人表:
id applicant_id applicant_note applicant_note_date
-----------------------------------------------------------
1 3 "Was good" 2013-05-01
1 4 "Was so-so" 2013-06-07
2 4 "Was bad" 2013-06-08
3 4 "Was great" 2013-06-10
员工表:
id employee_id employee_note employee_note_date
--------------------------------------------------------
1 10 "Was ok" 2013-07-20
1 10 "Was great" 2013-07-21
2 30 "Was bad" 2013-08-01
3 30 "Was so-so" 2013-08-02
我仅有的是employee_id
。 我想确保我从雇员和求职者那里都得到了所有便笺,并且希望将它们合并到同一列中,而不要使用具有NULL
值的重复列。 我想返回如下结果:
note date type
------------------------------------------------
"Was so-so" 2013-06-07 applicant
"Was bad" 2013-06-08 applicant
"Was great" 2013-06-10 applicant
"Was ok" 2013-07-20 employee
"Was great" 2013-07-21 employee
我现在的位置是:
SELECT
applicants.applicant_note AS note,
applicants.applicant_note_date AS date,
employees.employee_note AS note,
employees.employee_note_date AS date
IF(applicants.applicant_id IS NULL, 'employee', 'applicant') as type
FROM
employees
JOIN
people
ON
people.employee_id = employees.employee_id
JOIN
applicants
ON
applicants.applicant_id = people.applicant_id
WHERE
employees.employee_id = 10
有没有办法仅使用SQL来完成此任务? 还是我必须运行单独的查询才能获得申请人ID和员工ID?
您需要使用UNION ALL
SELECT employee_note note,
employee_note_date date,
'employee' type
FROM people a
INNER JOIN employees b
ON a.employee_ID = b.employee_ID
WHERE a.employee_ID = 10
UNION ALL
SELECT applicant_note note,
applicant_note_date date,
'applicant' type
FROM people a
INNER JOIN applicants b
ON a.applicant_id = b.applicant_id
WHERE a.employee_ID = 10
最简单的方法是复制您要求的内容,以使用UNION。 您可以从employees表中使用employee_id = 10。 对于申请人,您可以使用子查询,其中从employee_id = 10的人员表中提取applicant_id。
SELECT employee_note note,
employee_note_date date,
'employee' type
FROM employees e
WHERE e.employee_id = 10
UNION
SELECT applicant_note note,
applicant_note_date date,
'applicant' type
FROM applicants a
WHERE applicant_id = (SELECT applicant_id FROM people WHERE employee_id = 10)
使用JOIN的一个优点是可以将查询转换为派生表,从而允许在查询末尾用一个位置指示employee_id(或通过稍作修改将列表限制为applicant_id或people.id)。 此外,该表还可以包含people.id,以确保在查询中显示正确的人。 例如:
SELECT * FROM (
SELECT p.id person,
employee_note note,
employee_note_date date,
'employee' type
FROM employees e
JOIN people p on p.employee_id = e.employee_id
UNION
SELECT p.id person,
applicant_note note,
applicant_note_date date,
'applicant' type
FROM applicants a
JOIN people p on p.applicant_id = a.applicant_id
) q
WHERE q.person in(SELECT id FROM people WHERE employee_id = 10)
创建三个表的语句如下。
CREATE TABLE `people` (`id` int(11) NOT NULL, `applicant_id` int(11) NOT NULL,
`employee_id` int(11) NOT NULL, PRIMARY KEY (`id`),
KEY `applicant_id_index` (`applicant_id`),
KEY `employee_id_index` (`employee_id`)) ENGINE=InnoDB DEFAULT CHARSET=utf8;
CREATE TABLE `employees` (`employees_id` int(11) NOT NULL AUTO_INCREMENT,
`id` int(11) NOT NULL, `employee_id` int(11) NOT NULL,
`employee_note` varchar(12) DEFAULT NULL,
`employee_note_date` datetime DEFAULT NULL,
PRIMARY KEY (`employees_id`),
KEY `employee_id_index` (`employee_id`)
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;
CREATE TABLE `applicants` (
`applicants_id` int(11) NOT NULL AUTO_INCREMENT,
`id` int(11) NOT NULL,
`applicant_id` int(11) NOT NULL,
`applicant_note` varchar(12) DEFAULT NULL,
`applicant_note_date` datetime DEFAULT NULL,
PRIMARY KEY (`applicants_id`),
KEY `applicant_id_index` (`applicant_id`)
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;
INSERT INTO `employees` VALUES (1,1,10,'Was ok','2013-07-20 00:00:00'),
(2,1,10,'Was great','2013-07-21 00:00:00'),(3,2,30,'Was bad','2013-08-01 00:00:00'),
(4,3,30,'Was so-so','2013-08-02 00:00:00');
INSERT INTO `people` VALUES (1,3,6),(2,4,10),(3,12,30);
INSERT INTO `applicants` VALUES (1,1,3,'Was good','2013-05-01 00:00:00'),
(2,1,4,'Was so-so','2013-06-07 00:00:00'),
(3,2,4,'Was bad','2013-06-08 00:00:00'),
(4,3,4,'Was great','2013-06-10 00:00:00');
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