[英]How to plot NA bar with ggplot2
我想绘制一个条形图,其中显示了男性,女性和NA的数量。 问题是,当我添加选项fill=gender
以使条纹着色时,我会丢失NA条。 我应该使用什么选项来保持NA栏的颜色?
name <- c("Paul","Clare","John","What","Are","Robert","Alice","Jake")
gender <- c("male","female","male",NA,NA,"male","female","male")
df <- data.frame(name,gender)
ggplot(subset(df, gender=="male" | gender=="female" | is.na(gender)), aes(x=gender, fill=gender)) +
geom_bar() +
labs(x=NULL, y="Frequency") +
scale_fill_manual(values=c("red", "blue", "black"))
我只是重新编写它,个人 - 给你的观众一些比传说中的“NA”更好的东西。
# Recoding is easier with this off. When you want a factor, you'll know.
options(stringsAsFactors = FALSE)
library(ggplot2)
# Set up the data.frame
name <- c("Paul","Clare","John","What","Are","Robert","Alice","Jake")
gender <- c("male","female","male",NA,NA,"male","female","male")
df <- data.frame(name,gender)
# Convert NAs to "Unknown"
df$gender[is.na(df$gender)] <- "Unknown"
ggplot(df, aes(x=gender, fill=gender)) +
geom_bar() +
labs(x=NULL, y="Frequency") +
scale_fill_manual("Gender", values=c("red", "blue", "black"))
如果您确实必须按原样使用您的NA,则可以将性别纳入不排除NA的因素:
# Convert to a factor, NOT excluding NA values
df$gender <- factor(df$gender, exclude = NULL)
ggplot(df, aes(x=gender, fill = gender)) +
geom_bar(na.rm = FALSE) +
labs(x=NULL, y="Frequency") +
scale_fill_manual("Gender",
values=c("red", "blue", "black"))
NA仍未显示在图例中 - ggplot不希望在这里绘制NA,这就是为什么通常更容易重新编码它们,就像我在其他答案中那样。 无论哪种方式,我认为你将不得不修改你的性别变量。
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