[英]How to get the average number of minutes from datetime?
我想要做的是显示技术人员对每张票据的平均分钟数,但只显示平均值大于或等于每张票的总平均分钟数。 但你不能在日期时间使用avg。
我知道这是非常错误的,但这是我开始的:
select user_firstname + ' ' + user_lastname as technician_name,
avg(ticket_requestdate - ticket_closeddate) as average_minutes_per_ticket
from hd_users
join hd_tickets on ticket_requestor_id=user_id
where user_is_technician = '1'
having avg(ticket_requestdate - ticket_closeddate) >=
(select avg(ticket_requestdate - ticket_closeddate) from hd_users)
我会在子查询中使用datediff()和分钟
datediff(minute,datestart,dateend)
然后你得到分钟数作为int然后你可以做avg()
要么
avg(datediff(minute,datestart,dateend))
----编辑----我猜有点因为我不知道你的表结构,但是这个怎么样
select user_firstname + ' ' + user_lastname as technician_name,
avg(Datediff(minute,ticket_requestdate,ticket_closeddate)) as average_minutes_per_ticket
from hd_users
join hd_tickets on ticket_requestor_id=user_id
where user_is_technician = '1'
GROUP BY user_firstname, user_lastname
having avg(Datediff(minute,ticket_requestdate,ticket_closeddate)) >=
(select avg(Datediff(minute,ticket_requestdate,ticket_closeddate)) from hd_users)
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