[英]Converting hexadecimal to decimal in python
我正在尝试编写一个将十六进制转换为十进制的函数。 我有两个问题。 我无法用数字替换所有字母。 它替换字母然后停止。 其次,如何获得它以便连续地将每个整数相加?
def toDecimal(hexidecimal):
decimal=[hexidecimal[i:i+1] for i in range(0,len(hexidecimal), 1)]
for i in range(0,len(decimal)):
if 'a' in decimal:
decimal[i]='10'
if 'b' in decimal:
decimal[i]='11'
if 'c' in decimal:
decimal[i]='12'
if 'd' in decimal:
decimal[i]='13'
if 'e' in decimal:
decimal[i]='14'
if 'f' in decimal:
decimal[i]='15'
return decimal
#Above I try to convert any letters into a number value
for i in range(0,len(decimal)):
converted_decimal=decimal[i]*(16**i)
total_decimal=converted_decimal+converted_decimal
return total_decimal
#Here I'm trying to add each converted decimal
您的代码中有很多问题。 让我们来看一下:
hexidecimal= "7ac8965f" #hexadecimal value
decimal=[hexidecimal[i:i+1] for i in range(0,len(hexidecimal), 1)]
# >> decimal : ["7","a","c","8","9","6","5","f"]
for i in range(0,len(decimal)):
# first path : i = 0
# First Error : 'in' is a array-wide search.
# you want to use :'if decimal[i] == 'a' '
if 'a' in decimal: # a is in decimal (second pos) so decimal[0] is modified !
decimal[i]='10'
# >> decimal : ["10","a","c","8","9","6","5","f"]
if 'b' in decimal:
decimal[i]='11'
if 'c' in decimal:
decimal[i]='12'
if 'd' in decimal:
decimal[i]='13'
if 'e' in decimal:
decimal[i]='14'
if 'f' in decimal: # f is in decimal (last pos) so decimal[0] is modified !
decimal[i]='15'
# >> decimal : ["15","a","c","8","9","6","5","f"]
#Second Error : anticipated return
#Assuming the indentation is correct, the function exit here, on the
#first run of the function
return decimal
现在一个解决方案:
#dict for conversion (there are more elegant ways to do it,
# but this is good enough)
conversion_table = { '0' : 0 ,
'1' : 1 ,
'2' : 2 ,
'3' : 3 ,
.......
'a' : 10 ,
'b' : 11 ,
......
'f' : 15
}
hexidecimal= "7ac8965f" #hexadecimal value
hexa_list=[ digit for digit in hexidecimal]
# same thing as before, just more "elegant"
decimal = [ conversion_table[hex_digit] for hex_digit in hexa_list]
# convert everything in base10
# reduce the list
return reduce( lambda x,y : x*16 + y, decimal )
我认为阅读该惯用的python教程对您会有所帮助: http : //python.net/~goodger/projects/pycon/2007/idiomatic/handout.html
def hex2dec(hexadecimal):
conversion_table = {'A': 10, 'B': 11, 'C': 12, 'D': 13, 'E': 14, 'F': 15}
hex_list = list(hexadecimal)
for index, number in enumerate(hex_list):
number = number.upper()
if number in conversion_table:
hex_list[index] = conversion_table[number]
int_list = [int(number) for number in hex_list]
return reduce(lambda x, y: x*16+y, int_list)
print hex2dec('7Ac8965f') # 2059966047
我在这里很有趣,但是要重写您的功能...
def toDecimal(hexadecimal):
decimal = int(hexadecimal, 16)
return decimal
toDecimal('0xdeadbeef')
我想您是在重新发明轮子,只是为了看看它是如何完成的? :)
有一种更简单的方法可以做到这一点:
大的东西:
>>> s = "6f48f8248e828ce82f82"
>>> int(s, 16)
525528725744949635067778L
较小的东西:
>>> int('BF', 16)
191
在数字前添加0x
不会更改最终结果。
作为功能:
def hex2dec(s):
"""return the integer value of a hexadecimal string s"""
return int(s, 16)
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