将2个单独的SQL查询与单独的select语句组合

Question

我是sql和vb的新手，所以我想知道是否有人可以帮助我，这就是我现在拥有的表

id total_leadsource total_opportunity
2   1                 3
2   8                 16 

我想结合相同id的total_leadsource和total_opportunity

SELECT distinct id,LeadSource,SUM (WeightedAmount) as Weighted_Amount,
       COUNT(distinct oppLeadSourceID) + COUNT (distinct case when oppLeadSourceID is null then 0 end) as Total_LeadSource,
       count(OppLeadSourceID) as Total_Opportunity
FROM leadS A
LEFT JOIN opportunity B on B.Source = A.id
WHERE (OwnerCode =1486 
       OR AOCode =1486 
       OR PM = 1486 )
GROUP BY id,LeadSource
UNION 
SELECT distinct id,LeadSource,SUM (WeightedAmount) as Weighted_Amount,
       COUNT(distinct oppLeadSourceID) + COUNT (distinct case when oppLeadSourceID is null then 0 end) as Total_LeadSource,
       count(OppLeadSourceID) as Total_Opportunity
FROM leadS  A
LEFT JOIN opportunity B on B.Source = A.id
WHERE (OwnerCode =55856 
       OR AOCode =55856 
       OR PM = 55856 )
GROUP BY id,LeadSource

Answer 1

您不需要使用UNION 。 只需使用匹配两个条件的WHERE子句即可。

SELECT id,LeadSource,SUM (WeightedAmount) as Weighted_Amount,
       COUNT(distinct oppLeadSourceID) + COUNT(distinct case when oppLeadSourceID is null then 0 end) as Total_LeadSource,
       COUNT(OppLeadSourceID) as Total_Opportunity
FROM leadS A
LEFT JOIN opportunity B on B.Source = A.id
WHERE (OwnerCode IN (1486, 55856)
       OR AOCode IN (1486, 55856)
       OR PM IN (1486, 55856))
GROUP BY id,LeadSource

另请注意，在使用GROUP BY ，无需使用SELECT DISTINCT ，因为后者可以确保每一行都是不同的。