[英]Combining 2 separate sql queries with separate select statement
我是sql和vb的新手,所以我想知道是否有人可以幫助我,這就是我現在擁有的表
id total_leadsource total_opportunity
2 1 3
2 8 16
我想結合相同id的total_leadsource和total_opportunity
SELECT distinct id,LeadSource,SUM (WeightedAmount) as Weighted_Amount,
COUNT(distinct oppLeadSourceID) + COUNT (distinct case when oppLeadSourceID is null then 0 end) as Total_LeadSource,
count(OppLeadSourceID) as Total_Opportunity
FROM leadS A
LEFT JOIN opportunity B on B.Source = A.id
WHERE (OwnerCode =1486
OR AOCode =1486
OR PM = 1486 )
GROUP BY id,LeadSource
UNION
SELECT distinct id,LeadSource,SUM (WeightedAmount) as Weighted_Amount,
COUNT(distinct oppLeadSourceID) + COUNT (distinct case when oppLeadSourceID is null then 0 end) as Total_LeadSource,
count(OppLeadSourceID) as Total_Opportunity
FROM leadS A
LEFT JOIN opportunity B on B.Source = A.id
WHERE (OwnerCode =55856
OR AOCode =55856
OR PM = 55856 )
GROUP BY id,LeadSource
您不需要使用UNION
。 只需使用匹配兩個條件的WHERE
子句即可。
SELECT id,LeadSource,SUM (WeightedAmount) as Weighted_Amount,
COUNT(distinct oppLeadSourceID) + COUNT(distinct case when oppLeadSourceID is null then 0 end) as Total_LeadSource,
COUNT(OppLeadSourceID) as Total_Opportunity
FROM leadS A
LEFT JOIN opportunity B on B.Source = A.id
WHERE (OwnerCode IN (1486, 55856)
OR AOCode IN (1486, 55856)
OR PM IN (1486, 55856))
GROUP BY id,LeadSource
另請注意,在使用GROUP BY
,無需使用SELECT DISTINCT
,因為后者可以確保每一行都是不同的。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.