[英]ORACLE SQL: Combining 2 rows of 2 separate select queries
你好,我對 SQL 很陌生,我有一個問題。 我有 3 表工作、收入和成本。 job.unid = cost.job_unid 和 Revenue.job_unid
我想找到每項工作的總收入和成本,然后在一行中找到每項工作的利潤:
標題看起來像這樣:工作編號、總收入、總成本、損益 (Rev-Cost)
我試圖做一個單一的查詢,但在互聯網上搜索解決方案后,我似乎應該單獨查詢收入和成本,然后使用聯合所有進行組合。
現在我這樣做:
select m,
rlc,
rvatlc,
rtotlc,
clc,
cvatlc,
ctotlc
from(
(select decode(j.consolno,null,j.shpno,j.consolno) m,
sum(nvl(r.amtlc,0)) rlc,
sum(nvl(r.vatamtlc,0)) rvatlc,
sum(nvl(r.amtlc,0))+sum(nvl(r.vatamtlc,0)) rtotlc,
0 clc,
0 cvatlc,
0 ctotlc
from
job j
full join revenue r on j.unid=r.job_unid
where j.voidby is null and decode(j.consolno,null,j.shpno,j.consolno)='SHSEM00131'
group by decode(j.consolno,null,j.shpno,j.consolno)
)
union all
(select decode(j.consolno,null,j.shpno,j.consolno) m,
0 rlc,
0 rvatlc,
0 rtotlc,
sum(nvl(c.amtlc,0)) clc,
sum(nvl(c.vatamtlc,0)) cvatlc,
sum(nvl(c.amtlc,0))+sum(nvl(c.vatamtlc,0)) ctotlc
from
job j, cost c
where j.voidby is null and j.unid=c.job_unid and decode(j.consolno,null,j.shpno,j.consolno)='SHSEM00131'
group by decode(j.consolno,null,j.shpno,j.consolno)
))
結果是:我不確定你是否能看到,但它是 2 行:1 是收入,1 是成本。
我想結合這兩行
嘗試這個。
select m,
sum(rlc),
sum(rvatlc),
sum(rtotlc),
sum(clc),
sum(cvatlc),
sum(ctotlc)
from(
(select decode(j.consolno,null,j.shpno,j.consolno) m,
sum(nvl(r.amtlc,0)) rlc,
sum(nvl(r.vatamtlc,0)) rvatlc,
sum(nvl(r.amtlc,0))+sum(nvl(r.vatamtlc,0)) rtotlc,
0 clc,
0 cvatlc,
0 ctotlc
from
job j
full join revenue r on j.unid=r.job_unid
where j.voidby is null and decode(j.consolno,null,j.shpno,j.consolno)='SHSEM00131'
group by decode(j.consolno,null,j.shpno,j.consolno)
)
union all
(select decode(j.consolno,null,j.shpno,j.consolno) m,
0 rlc,
0 rvatlc,
0 rtotlc,
sum(nvl(c.amtlc,0)) clc,
sum(nvl(c.vatamtlc,0)) cvatlc,
sum(nvl(c.amtlc,0))+sum(nvl(c.vatamtlc,0)) ctotlc
from
job j, cost c
where j.voidby is null and j.unid=c.job_unid and decode(j.consolno,null,j.shpno,j.consolno)='SHSEM00131'
group by decode(j.consolno,null,j.shpno,j.consolno)
)) group by m;
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