为电子邮件选择DISTINCT，但还会获得另一列

Question

尝试仅获取唯一的电子邮件，但还要显示运送名称。

$sql=mysql_query("SELECT DISTINCT(email) As email FROM tbl_order");
while($row = mysql_fetch_array($sql))
{
echo " ".$row['shipping_name'].",".$row['email']." <br />";
}

但是它没有显示运输名称，非常有帮助，非常感谢。

Answer 1

尝试这个 ：

SELECT DISTINCT(email) As email,shipping_name FROM tbl_order" ;

Answer 2

做这个

("SELECT DISTINCT(email) AS email, shipping_name FROM tbl_order")

要么

("SELECT email, shipping_name FROM tbl_order GROUP BY email")

Answer 3

为您提供确切的代码：

$resultArray = array();
$sql=mysql_query("SELECT DISTINCT(email) as email,shipping_name FROM tbl_order");
$i = 0;
while($row = mysql_fetch_array($sql))
{
//echo " ".$row['shipping_name'].",".$row['email']." <br />";
$resultArray[$i]['shipping_name'] = $row['shipping_name'];
$resultArray[$i]['email'] = $row['email'];
$i++;
}
var_dump($resultArray);

Answer 4

 $sql=mysql_query("SELECT DISTINCT(email) As email,shipping_name FROM tbl_order");
while($row = mysql_fetch_array($sql))
{
echo " ".$row['shipping_name'].",".$row['email']." <br />";
}