為電子郵件選擇DISTINCT，但還會獲得另一列

Question

嘗試僅獲取唯一的電子郵件，但還要顯示運送名稱。

$sql=mysql_query("SELECT DISTINCT(email) As email FROM tbl_order");
while($row = mysql_fetch_array($sql))
{
echo " ".$row['shipping_name'].",".$row['email']." <br />";
}

但是它沒有顯示運輸名稱，非常有幫助，非常感謝。

Answer 1

嘗試這個 ：

SELECT DISTINCT(email) As email,shipping_name FROM tbl_order" ;

Answer 2

做這個

("SELECT DISTINCT(email) AS email, shipping_name FROM tbl_order")

要么

("SELECT email, shipping_name FROM tbl_order GROUP BY email")

Answer 3

為您提供確切的代碼：

$resultArray = array();
$sql=mysql_query("SELECT DISTINCT(email) as email,shipping_name FROM tbl_order");
$i = 0;
while($row = mysql_fetch_array($sql))
{
//echo " ".$row['shipping_name'].",".$row['email']." <br />";
$resultArray[$i]['shipping_name'] = $row['shipping_name'];
$resultArray[$i]['email'] = $row['email'];
$i++;
}
var_dump($resultArray);

Answer 4

 $sql=mysql_query("SELECT DISTINCT(email) As email,shipping_name FROM tbl_order");
while($row = mysql_fetch_array($sql))
{
echo " ".$row['shipping_name'].",".$row['email']." <br />";
}