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[英]parse JSON string to NSDictionary into array of objects Objective C
[英]parse JSON string into array of objects Objective C
我有一个从休息Web服务请求返回的JSON字符串,我想将此字符串解析为确定类的对象Array,这是JSON字符串
[
{
"validationCode": null,
"FirstName": "Samer",
"LastName": "Shame",
"MobileNumber": "0991992993",
"SimNumber": null,
"Email": null,
"PhoneNumber": "0991992994",
"Name": "Abo Alshamat",
"ID": 1
},
{
"validationCode": null,
"FirstName": "Ahmad",
"LastName": "Ali",
"MobileNumber": "0992993994",
"SimNumber": null,
"Email": null,
"PhoneNumber": "0992993995",
"Name": "AL-Kamal",
"ID": 2
},
{
"validationCode": null,
"FirstName": null,
"LastName": null,
"MobileNumber": "0993377800",
"SimNumber": null,
"Email": null,
"PhoneNumber": null,
"Name": "Abo-MAhmoud",
"ID": 12
},
{
"validationCode": null,
"FirstName": "William",
"LastName": "Ammar",
"MobileNumber": "0993994995",
"SimNumber": null,
"Email": null,
"PhoneNumber": "0993994996",
"Name": "Four Season",
"ID": 3
},
{
"validationCode": null,
"FirstName": "Ammar",
"LastName": "William",
"MobileNumber": "0999555777",
"SimNumber": null,
"Email": null,
"PhoneNumber": null,
"Name": "uuuuu",
"ID": 20
},
{
"validationCode": null,
"FirstName": null,
"LastName": null,
"MobileNumber": "0999888777",
"SimNumber": null,
"Email": null,
"PhoneNumber": null,
"Name": "NewOneFromI2",
"ID": 18
},
{
"validationCode": null,
"FirstName": null,
"LastName": null,
"MobileNumber": "0999998997",
"SimNumber": null,
"Email": null,
"PhoneNumber": "0999999998",
"Name": "JOURY",
"ID": 4
},
{
"validationCode": null,
"FirstName": null,
"LastName": null,
"MobileNumber": "202020",
"SimNumber": null,
"Email": null,
"PhoneNumber": null,
"Name": "TestTestRestaurant,Ammar,Hamed",
"ID": 19
}
]
我想从中获取实例的类是:
@interface Restaurant : NSObject
@property (nonatomic,strong) NSString *ID;
@property (nonatomic,strong) NSString* FirstName;
@property (nonatomic,strong) NSString* LastName;
@property (nonatomic,strong) NSString* MobileNumber;
@property (nonatomic,strong) NSString* simNumber;
@property (nonatomic,strong) NSString* PhoneNumber;
@property (nonatomic,strong) NSString* Name;
@end
什么是最好的方法,对不起,也许问题来自基础知识,但我是客观C的新手
感谢您的时间。
我建议为你的Restaurant
类实现一个init方法。
-(instancetype) initWithParameters:(NSDictionary*)parameters
{
self = [super init];
if (self) {
//initializations
_validationCode = parameters[@"validationCode"]; // may be NSNull
_firstName = [parameters[@"FirstName"] isKindOfClass:[NSNull class]] ? @""
: parameters[@"FirstName"];
...
}
return self;
}
注意:你可能有JSON Null的事实,使你的初始化有点复杂。 当相应的JSON值为Null时,您需要决定如何初始化属性。
您的parameters
字典将是您从服务器获得的JSON数组中的第一级字典。
首先,创建一个JSON表示,即JSON中的NSArray对象:
NSError* localError;
id restaurantsObjects = [NSJSONSerialization JSONObjectWithData:data
options:0
error:&localError];
IFF没有失败,你的restaurantsObjects
现在应该是一个NSArray
对象,包含餐馆作为NSDictionary
s。
现在,创建一个将使用Restaurant
对象填充的NSMutableArray
将是直截了当的:
NSMutableArray* restaurants = [[NSMutableArray alloc] init];
for (NSDictionary* restaurantParameters in restaurantsObjects) {
Restaurant* restaurant = [Restaurant alloc] initWithParameters: restaurantParameters];
[restaurants addObject:restaurant];
}
最后,您可以在某个控制器中设置一个属性restaurants
:
self.restaurants = [restaurants copy];
你的JSON有一系列的字典...首先将你的数据转换为NSArray。
NSError *jsonError = nil;
NSArray *jsonArray = (NSArray *)[NSJSONSerialization JSONObjectWithData:jsonData options:nil error:&jsonError];
现在你有一系列JSON字典迭代。
for (NSDictionary *dic in jsonArray){
// Now you have dictionary get value for key
NSString *firstName = (NSString*) [dic valueForKey:@"FirstName"];//We are casting to NSString because we know it will return a string. do this for every property...
}
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