[英]Python: Trouble with loops and ranges
我是使用pygame以python语言编写游戏的新手。 这是一个基于光标的游戏,您可以在其中使用鼠标。 物体从屏幕顶部掉落,目的是抓住它们。 我使用范围函数来确定将要掉落的对象数。 我的代码确实有2个问题,我希望得到一些帮助。 我将在此处发布代码:
time = 150
level = 1
score = 0
class Bomb(pygame.sprite.Sprite):
def __init__(self):
pygame.sprite.Sprite.__init__(self)
self.image = load_image("Bomb.png")
screen = pygame.display.get_surface()
self.rect = self.image.get_rect()
def bomb_spawn(self):
self.rect.x = random.randrange(640)
self.rect.y = random.randrange(-200, -0) # Respawns at the top
def update(self):
if self.rect.y > 805: # Respawns if colliding with bottom screen
self.bomb_spawn()
if self.rect.x < 105: # I do have a border/margin so if the object spawns outside
self.bomb_spawn() # It will respawn
if level == 1:
self.rect.y += 3 # The falling speed of the object increases for each level
elif level == 2:
self.rect.y += 4
elif level == 3:
self.rect.y += 5
elif level == 4:
self.rect.y += 6
elif level == 5:
self.rect.y += 7
elif level == 6:
self.rect.y += 8
elif level == 7:
self.rect.y += 9
else:
self.rect.y += 10
if time <= 1: # Game over
self.kill()
class Clocks(pygame.sprite.Sprite):
def __init__(self):
pygame.sprite.Sprite.__init__(self)
self.image = load_image("Clock.png")
screen = pygame.display.get_surface()
self.rect = self.image.get_rect()
def clock_spawn(self):
self.rect.x = random.randrange(640)
self.rect.y = random.randrange(-200, -0)
def update(self):
if time < 100 and time >= 0: # Required for my current Clock range function
if self.rect.y > 805:
self.clock_spawn()
if self.rect.x < 105:
self.clock_spawn()
if level == 1:
self.rect.y += 3
elif level == 2:
self.rect.y += 4
elif level == 3:
self.rect.y += 5
elif level == 4:
self.rect.y += 6
elif level == 5:
self.rect.y += 7
elif level == 6:
self.rect.y += 8
elif level == 7:
self.rect.y += 9
else:
self.rect.y += 10
if time <= 1:
self.kill()
while done == False:
time -= 0.150 # timer
level = int(score/2000) + 1 # new level when you reach 2000 points.
现在我要讲到重点,我在范围和循环方面遇到了一些麻烦。 首先从时钟开始,我希望仅在计时器低于100的情况下才产生时钟。我设法做到了这一点,但还有一个问题。 目前,我使用clock.rect.x = 2000,对rect.y相同,这意味着它们在我的屏幕之外生成。 我希望精灵消失/删除/杀死,然后在计时器低于100时重新生成。
for i in range(1):
clocks = Clocks()
if time > 100:
clocks.rect.x = 2000 # spawns outside my screen, I want to change this.
clocks.rect.y = 2000
elif time < 100:
clocks.rect.x = random.randrange(640)
clocks.rect.y = random.randrange(-200, -20)
ClockGroup.add(clocks)
接下来,我的炸弹范围确实有问题。 我想增加每个新级别的范围量。 例如:在1级中将有1枚炸弹,在2级中将有2枚炸弹,依此类推。
for i in range(1):
bomb = Bomb()
bomb.rect.x = random.randrange(640)
bomb.rect.y = random.randrange(-200, -20)
BombGroup.add(bomb)
#I have tried some methods but none of them were working.
#Here is what I went with
if level == 2: # This is where I am at, I don't know how to proceed.
链接到完整代码: http : //pastebin.com/cpQwi2fR任何帮助将不胜感激。 真诚的HJ。
如果你想有n
在水平炸弹n
试试这个:
for _ in range(level): #level goes here
bomb = Bomb()
bomb.rect.x = random.randrange(640)
bomb.rect.y = random.randrange(-200, -20)
BombGroup.add(bomb)
也是这个片段:
if level == 1:
self.rect.y += 3 # The falling speed of the object increases for each level
elif level == 2:
self.rect.y += 4
elif level == 3:
self.rect.y += 5
elif level == 4:
self.rect.y += 6
elif level == 5:
self.rect.y += 7
elif level == 6:
self.rect.y += 8
elif level == 7:
self.rect.y += 9
else:
self.rect.y += 10
与此代码段相同:
self.rect.y += (level + 2) if level < 8 else 10
现在有了您的精灵问题,因为我从未使用过pygame,所以我无济于事。
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