获取表单日期差异
[英]Get form date difference
问题描述
我有一个带有两个输入的 html 表单
<input type="datetime" name="start" id="start" ></input>
<input type="datetime" name="stop" id="stop" ></input>
还有一个send.php ，它向我发送表单内容。
在send.php 中，我想计算 STOP 和 START 之间的天数差异，如差异 = STOP - START。 如果时间差为正且大于 1 小时，那么我希望多添加一天。
If START = 02/01/2014 14:58:21
If STOP = 07/01/2014 14:59:21
然后输出 = 5 天
If START = 02/01/2014 14:58:21
If STOP = 07/01/2014 14:59:21
然后输出 = 6 天
我怎么能做到这一点？
send.php应该通过邮件发送结果。
所以在我的.html我有类似的东西
<form action="send.php" method="get">
<div id="datetimepicker" class="input-append date">
<input type="datetime" name="START" id="START" ></input>
<span class="add-on">
<i data-time-icon="icon-time" data-date-icon="icon-calendar"></i>
</span>
</div>
<div id="datetimepicker" class="input-append date">
<input type="datetime" name="STOP" id="STOP" ></input>
<span class="add-on">
<i data-time-icon="icon-time" data-date-icon="icon-calendar"></i>
</span>
</div>
</form>
我的send.php是
<?php
@$pfw_ip= $_SERVER['REMOTE_ADDR'];
@$START= $_GET['START'];
@$STOP= $_GET['STOP'];
@$email= addslashes($_GET['email']);
$_start = new DateTime($_POST['start']); // or new DateTime($_POST['start']);
$_stop = new DateTime($_POST['stop']);// or new DateTime($_POST['stop']);
$interval = $_start->diff($_stop);
$to = "me@me.com";
$subject = "Calculator";
$headers = "From: $email\r\n";
$headers .= "Reply-To: $email\r\n";
$headers .= "Return-Path: $email\r\n";
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
$message = "<html><body style=\"font-family:Calibri; font-size:14.5px;\">";
$message .= " result between $STOP and $START is ....days
ID: $pfw_ip <br/>";
$message .= "</body></html>";
mail($to,$subject,$message,$headers);
?>
the error i get now is Catchable fatal error: Object of class DateInterval could not be converted to string in
2 个解决方案
解决方案1
0 2014-01-13 13:24:07
如果您使用的是 PHP >= 5.3
用这个：
$_start = new DateTime('02/01/2014 14:58:21'); // or new DateTime($_POST['start']);
$_stop = new DateTime('02/05/2014 14:58:21'); // or new DateTime($_POST['stop']);
$interval = $_start->diff($_stop);
echo $interval->format('%a days'); // Should output "4 days".
//for (-)ve and (+)ve values, use:
echo $interval->format('%R%a days'); // Should output "+4 days".
所以，在你的 send.php 中应该是这样的：
<?php
$pfw_ip= $_SERVER['REMOTE_ADDR'];
$email= addslashes($_GET['email']);
// Calculating the difference
$_start = new DateTime($_GET['start']);
$_stop = new DateTime($_GET['stop']);
$interval = $_start->diff($_stop);
// Preparing email content
$to = "me@me.com";
$subject = "Calculator";
$headers = "From: $email\r\n";
$headers .= "Reply-To: $email\r\n";
$headers .= "Return-Path: $email\r\n";
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
$message = "<html><body style=\"font-family:Calibri; font-size:14.5px;\">";
$message .= " result between $STOP and $START is ".$interval->format('%R%a days')."
ID: $pfw_ip <br/>";
$message .= "</body></html>";
mail($to,$subject,$message,$headers);
?>
解决方案2
0 2014-01-13 13:25:04
最简单的方法是将日期转换为 unix 时间戳
$start = strtotime($_POST['START']);
$end = strtotime($_POST['END']);
$interval = $end - $start;
因为答案是在几秒钟内，你可以做简单的数学计算来得到天数
$days = $interval / 86400 // number of seconds in a day
您还可以查看日期是否在一小时内
if ($interval > 3600)，依此类推
如何获得日期差异
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