SELECT语句的列数不同

Question

我尝试使用下面的代码，它说

所使用的SELECT语句的列数不同

因为在第二个查询中添加的距离列更多。我该如何解决这样的问题，或者没有距离列可以直接获得订单？我真的很感谢您的帮助。

SELECT * FROM
(
   SELECT * FROM user u
   INNER JOIN employee e ON (u.empid = e.empid)
   INNER JOIN awards a ON (u.empid = a.empid)
   WHERE u.empid = 123

   UNION

   SELECT * ( 3959 * acos( cos( radians(37) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(-122) )+ sin( radians(37) ) * sin( radians( lat ) ) ) ) AS distance
   FROM user u
   INNER JOIN employee e ON (u.empid = e.empid)
   INNER JOIN awards a ON (u.empid = a.empid)
   HAVING distance < 25
   ORDER BY distance
) a
ORDER BY timestamp DESC

Answer 1

这是因为自从您在2nd SELECT引入Distance以来，您的1st SELECT和2nd SELECT的列数有所不同。

因此，请尝试如下将第一个查询中的Distance为null或0。

SELECT * FROM
(
   SELECT *, 0 as Distance
   FROM user u
   INNER JOIN employee e ON (u.empid = e.empid)
   INNER JOIN awards a ON (u.empid = a.empid)
   WHERE u.empid = 123

   UNION

   SELECT *, ( 3959 * acos( cos( radians(37) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(-122) )+ sin( radians(37) ) * sin( radians( lat ) ) ) ) AS distance
   FROM user u
   INNER JOIN employee e ON (u.empid = e.empid)
   INNER JOIN awards a ON (u.empid = a.empid)
   HAVING distance < 25
   ORDER BY distance
) a
ORDER BY timestamp DESC

Answer 2

您可以通过在第一个查询中增加距离来解决此问题：

SELECT * FROM
(
   SELECT *, NULL as distance FROM user u
   INNER JOIN employee e ON (u.empid = e.empid)
   INNER JOIN awards a ON (u.empid = a.empid)
   WHERE u.empid = 123

   UNION

   SELECT *,  ( 3959 * acos( cos( radians(37) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(-122) )+ sin( radians(37) ) * sin( radians( lat ) ) ) ) AS distance
   FROM user u
   INNER JOIN employee e ON (u.empid = e.empid)
   INNER JOIN awards a ON (u.empid = a.empid)
   HAVING distance < 25
   ORDER BY distance
) a
ORDER BY timestamp DESC;