awk Lookup 2文件，打印匹配和Sencond Field的总和：

Question

我需要comapre两个文件f1.txt和f2.txt并获得匹配和不匹配，对于这种情况我要检查f1.txt的第二个字段是否匹配f2.txt的第一个字段，如果是的话打印f1.txt的整行并打印f2.txt的第一个字段和f2.txt的第二个字段的Sum。 并且在f1.txt上找不到匹配状态“NotFound”。

f1.txt

aa,10,cc,Jan-13
bb,20,cc,Feb-13
dd,50,cc,Mar-13

f2.txt

10,1500,ss
20,500,gg
10,2000,kk
10,15000,yy
20,500,zz,
35,250,tt

Output.txt的

aa,10,cc,Jan-13,10,18500
bb,20,cc,Feb-13,20,1000
dd,50,cc,Mar-13,NotFound,NotFound

Answer 1

这个awk应该这样做

awk -F, 'FNR==NR {a[$1]+=$2;next} {if ($2 in a) print $0,$2,a[$2]; else print $0,"NotFound","NotFound"}' OFS=, f2.txt f1.txt
aa,10,cc,Jan-13,10,18500
bb,20,cc,Feb-13,20,1000
dd,50,cc,Mar-13,NotFound,NotFound

它是如何工作的：

awk -F, '                                       #Set Field separator to ,
    FNR==NR {a[$1]+=$2;next}                    #Read data from file f2.txt using field #1 as index and sum field #2 in to array a
    {if ($2 in a)                               #Test if field #2 in f1.txt is found in a
        print $0,$2,a[$2]                       #If found, print line of f1.txt with sum and index from array
        else print $0,"NotFound","NotFound"     #If not found print line of f1.txt with NotFound
    }
    ' OFS=, f2.txt f1.txt                       #Set Output field separator to , and read files

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略短的版本：

awk -F, 'FNR==NR {a[$1]+=$2;next} {print $0 ","($2 in a?$2","a[$2]:"NotFound,NotFound")}' f2.txt f1.txt