Javascript：查找具有最高和第二高值的变量

Question

我想循环寻找最高和第二高的球员。 我在任何地方都找不到说明。

我有以下变量： Player2 = 50 Player1 = 25 Player2 = 50 Player3 = 14

我想在变量中保存最高和第二高的玩家。 var highest = highestplayer; var secondhighest = secondhigest;

Answer 1

您可以将播放器放在一个数组中并对数组进行排序：

players = [Player1, Player2, Player3];
players.sort(function(x, y) { return y - x; });

var highest = players[0];
var secondhighest = players[1];

如果需要玩家和积分，则应考虑使用以下对象：

Player1 = { name: 'Player1', points: 25 };
Player2 = { name: 'Player2', points: 50 };
Player3 = { name: 'Player3', points: 14 };

players = [Player1, Player2, Player3];
players.sort(function(x, y) { return y.points - x.points; });

var highest = players[0];
var secondhighest = players[1];

alert(highest.name + ': ' + highest.points);
alert(secondhighest.name + ': ' + secondhighest.points);

Answer 2

首先，玩家需要的不仅仅是存储的整数，所以您可以分辨出哪个是哪个。 然后它们需要放在一个数组中。

var player1 = {name:"Player 1",score:"25"};
var player2 = {name:"Player 2",score:"50"};
var player3 = {name:"Player 3",score:"14"};
var players = [player1,player2,player3];

那么您可以快速循环浏览并拉出最高的和第二个。

var highestplayer, secondhighest;
for (var i=players.length;i--;) { //quickly walks backwards through an array
  //if highest isn't set yet, or new player beats highest 
  if (!highestplayer || players[i].score > highestplayer.score) {
    //move highest down the ranks
    secondhighest = highestplayer;
    //set the new leader
    highestsplayer = players[i];

  }
  //if second not set or new player beats second
  else if (!secondhigest || player[i].score > secondhighest.score) {
    secondhighest = player[i];
  }
}

但是，如果要获得完整排名，则需要使用排序功能

players.sort(function(a,b) { return b.score-a.score });