Javascript - 在对象的 arrays 的 object 中找到最高值

Question

我有一个包含 arrays 对象的 object。 我试图找到 object 属性“sortOrder”的最大值，而无需手动遍历 arrays 和对象。

所以我的变量如下所示：

const myObj = {
 people: [
   0: {firstname: 'Dave', lastName: 'Jones', sortOrder: 22},
   1: {firstname: 'Jane', lastName: 'Smith', sortOrder: 11}
 ],
 otherPeople: [
   0: {firstname: 'Jen', lastName: 'SomeLastName', sortOrder: 33},
   1: {firstname: 'ExampleFirstName', lastName: 'ExampleLastName', sortOrder: 12}
 ]
};

所以我会尝试遍历这个最终找到，在这种情况下，最高的 sortOrder 33。不一定是数组索引或包含它的 object，只是数字。

谢谢

Answer 1

 const myObj = { people: [ {firstname: 'Dave', lastName: 'Jones', sortOrder: 22}, {firstname: 'Jane', lastName: 'Smith', sortOrder: 11} ], otherPeople: [ {firstname: 'Jen', lastName: 'SomeLastName', sortOrder: 33}, {firstname: 'ExampleFirstName', lastName: 'ExampleLastName', sortOrder: 12} ] }; const maxSortOrder = Object.values(myObj).reduce((max, arr) => { arr.forEach(({ sortOrder }) => { if(sortOrder > max) { max = sortOrder; } }); return max; }, 0); console.log(maxSortOrder);

Answer 2

（我不得不稍微更正您的输入数据：arrays 不包括您显示的索引号。）

最简单的方法是将 object 中的两个 arrays 合并为一个列表，然后使用reduce找到最大值：

 const myObj = { people: [ { firstname: 'Dave', lastName: 'Jones', sortOrder: 22 }, { firstname: 'Jane', lastName: 'Smith', sortOrder: 11 } ], otherPeople: [ { firstname: 'Jen', lastName: 'SomeLastName', sortOrder: 33 }, { firstname: 'ExampleFirstName', lastName: 'ExampleLastName', sortOrder: 12 } ] }; let allPeople = [...myObj.people, ...myObj.otherPeople]; let max = allPeople.reduce((maxSort, person) => { return Math.max(maxSort, person.sortOrder) }, 0)); console.log(max)

Answer 3

您可以按最高的 sortOrder 对它们进行排序，然后在每个数组中取最高元素中的较高者：

 const myObj = { people: [{ firstname: 'Dave', lastName: 'Jones', sortOrder: 22 }, { firstname: 'Jane', lastName: 'Smith', sortOrder: 11 } ], otherPeople: [{ firstname: 'Jen', lastName: 'SomeLastName', sortOrder: 33 }, { firstname: 'ExampleFirstName', lastName: 'ExampleLastName', sortOrder: 12 } ] }; Object.values(myObj).forEach(peopleArray => { peopleArray.sort((a, b) => b.sortOrder - a.sortOrder) }) let maxValue = Math.max(myObj.people[0].sortOrder, myObj.otherPeople[0].sortOrder) console.log(maxValue)

Answer 4

const myObj = {
people: [
    {firstname: 'Dave', lastName: 'Jones', sortOrder: 22},
    {firstname: 'Jane', lastName: 'Smith', sortOrder: 11}
],
otherPeople: [
    {firstname: 'Jen', lastName: 'SomeLastName', sortOrder: 33},
    {firstname: 'ExampleFirstName', lastName: 'ExampleLastName', sortOrder: 12}
]};

let maxSortOrder = 0;
for (const value of Object.values(myObj)) {
    maxSortOrder = value.reduce((acc, { sortOrder }) => sortOrder > acc ? sortOrder : acc, maxSortOrder);
};

console.log(maxSortOrder); //33