[英]Create JSON in javascript and create a file on webserver via ajax and php
[英]cannot connect to php file located on webserver through ajax?
根据一些研究,我认为XmlHttpRequest不允许直接进行跨域数据交换,因此下面的代码无法连接到存储在webserver(1freehosting.com)上的getstopname.php文件。
如何转换下面的Java脚本代码,使其可以直接访问存储在远程Web服务器上的php文件?
function getDirection(str)
{
if (str=="")
{
document.getElementById("select-choice-direction").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{
xmlhttp=new XMLHttpRequest();
}
else
{
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
$('#select-choice-stopname').html(xmlhttp.responseText).selectmenu( "refresh");
$('#select-choice-stopname-postuser').html(xmlhttp.responseText).selectmenu( "refresh");
}
}
xmlhttp.open("GET","http://www.xyz.com/getstopname.php?direction="+str.value+"&bus="+busnum+"&dayofweek="+dayofweek,true);
xmlhttp.send();
}
getstopname.php文件(存储在其他Web服务器上)
<?php
$bus = intval($_GET['bus']);
$q = $_GET['direction'];
$dayofweek = $_GET['dayofweek'];
$con=mysqli_connect("xyz.com","root","root123","db1","3306");
ct_db($con,"db1");
$result = mysqli_query($con,"SELECT StopNames FROM cfv_busstopnames WHERE UniqueBusId = '".$q."' and busnumber = ".$bus." and Dayofweek = '".$dayofweek."' ");
echo "<option>" . "Pick Stop Names? ". "</option>" ;
while($row = mysqli_fetch_array($result))
{
echo "<option>" . $row['StopNames'] . "</option>" ;
}
?>
您可以尝试允许CORS:
在getstopname.php
的最上方:
<?php
header("Access-Control-Allow-Origin: *"); //remember to replace the * with the domain the JavaScript is running from
$bus = intval($_GET['bus']);
$q = $_GET['direction'];
$dayofweek = $_GET['dayofweek'];
//rest of the code
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.