[英]R apply conversion to multiple columns of data.frame
我想将data.frame中的几列从chr转换为数值,我想在一行中完成。 这是我正在尝试做的事情:
items[,2:4] <- as.numeric(sub("\\$","",items[,2:4]))
但是我收到一个错误消息:
Warning message:
NAs introduced by coercion
如果我按列做它,尽管它起作用:
items[,2:2] <- as.numeric(sub("\\$","",items[,2:2]))
items[,3:3] <- as.numeric(sub("\\$","",items[,3:3]))
items[,4:4] <- as.numeric(sub("\\$","",items[,4:4]))
我在这里想念什么? 为什么要为多列指定此命令? 这是我不知道的奇怪的R特质吗?
示例数据:
Name, Cost1, Cost2, Cost3, Cost4
A, $10.00, $15.50, $13.20, $45.45
B, $45.23, $34.23, $34.24, $23.34
C, $23.43, $45.23, $65.23, $34.23
D, $76.34, $98.34, $90.34, $45.09
您的问题是, gsub
将其x
参数转换为character
。 如果一个list
( data.frame
实际上是一个list
)被转换为character
则会发生有线连接:
as.character(list(a=c("1", "1"), b="1"))
# "c(\"1\", \"1\")" "1"
# and "c(\"1\", \"1\")" can not convert into a numeric
as.numeric("c(\"1\", \"1\")")
# NA
一种解决方案是unlist
x
参数:
items[, 2:5] <- as.numeric(gsub("\\$", "", unlist(items[, 2:5])))
是的,这里有: apply
是您要查找的命令:
items<-read.table(text="Name, Cost1, Cost2, Cost3, Cost4
A, $10.00, $15.50, $13.20, $45.45
B, $45.23, $34.23, $34.24, $23.34
C, $23.43, $45.23, $65.23, $34.23
D, $76.34, $98.34, $90.34, $45.09", header=TRUE,sep=",")
items[,2:4]<-apply(items[,2:4],2,function(x){as.numeric(gsub("\\$","",x))})
items
Name Cost1 Cost2 Cost3 Cost4
1 A 10.00 15.50 13.20 $45.45
2 B 45.23 34.23 34.24 $23.34
3 C 23.43 45.23 65.23 $34.23
4 D 76.34 98.34 90.34 $45.09
一种更有效的方法是:
items[-1] <- lapply(items[-1], function(x) as.numeric(gsub("$", "", x, fixed = TRUE)))
items
# Name Cost1 Cost2 Cost3 Cost4
# 1 A 10.00 15.50 13.20 45.45
# 2 B 45.23 34.23 34.24 23.34
# 3 C 23.43 45.23 65.23 34.23
# 4 D 76.34 98.34 90.34 45.09
fun1 <- function() {
A[-1] <- lapply(A[-1], function(x) as.numeric(gsub("$", "", x, fixed=TRUE)))
A
}
fun2 <- function() {
A[, 2:ncol(A)] <- as.numeric(gsub("\\$", "", unlist(A[, 2:ncol(A)])))
A
}
fun3 <- function() {
A[, 2:ncol(A)] <- apply(A[,2:ncol(A)], 2, function(x) { as.numeric(gsub("\\$","",x)) })
A
}
这是一些示例数据和处理时间
set.seed(1)
A <- data.frame(Name = sample(LETTERS, 10000, TRUE),
matrix(paste0("$", sample(99, 10000*100, TRUE)),
ncol = 100))
system.time(fun1())
# user system elapsed
# 0.72 0.00 0.72
system.time(fun2())
# user system elapsed
# 5.84 0.00 5.85
system.time(fun3())
# user system elapsed
# 4.14 0.00 4.14
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