如果缺少数组元素，则PHP重建多维数组

Question

我有一个Multi-Dimesional数组，我想重建此数组，以便所有具有另一个数组具有的丢失数据（基本上替换丢失的数据）的所有第一级数组（ array[] ）。 我正在使用此数组构建图形，因此我需要用0填充缺失的区域，否则我的图形中会有巨大的空洞。

[numberof]是该给定图的数量。 [date]是发生的月份。 如您所见，我是今天（3） ASC订单：

电流输出

Array
 (
[First] => Array
    (
        [0] => Array
            (
                [numberof] => 1
                [date] => 12
            )

        [1] => Array
            (
                [numberof] => 2
                [date] => 1
            )

        [2] => Array
            (
                [numberof] => 2
                [date] => 2
            )

        [3] => Array
            (
                [numberof] => 25
                [date] => 3
            )

    )

[Second] => Array
    (
        [0] => Array
            (
                [numberof] => 1
                [date] => 1
            )

        [1] => Array
            (
                [numberof] => 2
                [date] => 2
            )

        [2] => Array
            (
                [numberof] => 1
                [date] => 3
            )

    )

[Third] => Array
    (
        [0] => Array
            (
                [numberof] => 1
                [date] => 2
            )

    )
)

期望的结果

Array
 (
[First] => Array
    (
        [0] => Array
            (
                [numberof] => 1
                [date] => 12
            )

        [1] => Array
            (
                [numberof] => 2
                [date] => 1
            )

        [2] => Array
            (
                [numberof] => 2
                [date] => 2
            )

        [3] => Array
            (
                [numberof] => 25
                [date] => 3
            )

    )

[Second] => Array
    (
        [0] => Array //ADDED and given a value of 0
            (
                [numberof] => 0
                [date] => 12
            )

        [1] => Array
            (
                [numberof] => 1
                [date] => 1
            )

        [2] => Array
            (
                [numberof] => 2
                [date] => 2
            )

        [3] => Array
            (
                [numberof] => 1
                [date] => 3
            )

    )

[Third] => Array
    (

        [0] => Array //ADDED and given a value of 0
            (
                [numberof] => 0
                [date] => 12
            )

        [1] => Array  //ADDED and given a value of 0
            (
                [numberof] => 0
                [date] => 1
            )
        [2] => Array
            (
                [numberof] => 1
                [date] => 2
            )

        [3] => Array //ADDED and given a value of 0
            (
                [numberof] => 0
                [date] => 3
            )
    )
)

在我看来这是不可能的。 但是也许我还没有掌握技能，到目前为止我已经尝试过了：

注意，这就是我大声说的 ..我只是无法理解该怎么做，遍历数组，检查它是否具有numbr值，如果没有添加它。 但是，如果最后一行是月份最多的那一行而第一个月只有1个月怎么办？

编辑

MySQL ：

$sql = sprintf("SELECT count(*) as numberOf, MONTH(s.sextime) as date FROM sex s, users u WHERE %s AND s.uid = u.uid AND s.sextime >= DATE_SUB(CURRENT_DATE, INTERVAL %d MONTH) GROUP BY MONTH(s.sextime) ORDER BY s.sextime ASC;", $type, $months);

这是PHP生成上述数组并调用sql的过程：

    $info['info']['First'] = $this->dataStore->grabSexesByMonth('AND s.sexnumber=1');
    $info['info']['Second'] = $this->dataStore->grabSexesByMonth('AND s.sexnumber=2');
    $info['info']['Third'] = $this->dataStore->grabSexesByMonth('AND s.sexnumber=3');

Answer 1

一个三步过程可能会起作用：

$fillTo = array('key'=>'','count'=>0);
foreach($array as $k => $data) {
    if (count($data) > $fillTo['count']) {
        $fillTo['key'] = $k;
        $fillTo['count'] = count($data);
    }
}

$fillData = $array[$fillTo['key']];
foreach($fillData as $k => &$data) {
    $data['numberof'] => 0;
}

foreach($array as $k => &$data) {
    if ($k === $fillTo['key'])
        continue;

    $data = $data + $fillData;
}

var_dump($array);

Answer 2

不幸的是， MySQL没有设置返回函数，例如PostgreSQL generate_series 。 这使事情变得有些复杂，因为您需要以编程方式生成所有日期的集合。 另外，您应该使用EXTRACT(YEAR_MONTH FROM sextime)而不是MONTH(sextime) ，否则您将混合不同年份的月份的总和。

$months = 4;

# emulate GENERATE_SERIES
for ($i = $months-1; $i >= 0; $i--) {
  $gen_series[] = "SELECT EXTRACT(YEAR_MONTH FROM CURRENT_DATE - INTERVAL $i MONTH) extr";
}
$gen_series = join(' UNION ', $gen_series);


$sql = sprintf("SELECT
                  fll.sexnumber,
                  fll.extr as date,
                  COUNT(u.uid) as numberOf
                FROM
                  (SELECT
                    dts.extr,
                    sxn.sexnumber
                  FROM
                    (%s) dts,
                    (SELECT DISTINCT sexnumber FROM sex) sxn) fll LEFT JOIN sex s
                ON
                  fll.extr = EXTRACT(YEAR_MONTH FROM s.sextime) AND fll.sexnumber=s.sexnumber LEFT JOIN users u
                ON
                  s.uid = u.uid
                GROUP BY
                  fll.sexnumber,
                  fll.extr
                ORDER BY
                  fll.sexnumber,
                  fll.extr", $gen_series);

echo $sql;

上面的PHP代码将输出以下SQL查询。

SELECT
  fll.sexnumber,
  fll.extr as date,
  COUNT(u.uid) as numberOf
FROM
  (SELECT
    dts.extr,
    sxn.sexnumber
  FROM
    (SELECT EXTRACT(YEAR_MONTH FROM CURRENT_DATE - INTERVAL 3 MONTH) extr UNION SELECT EXTRACT(YEAR_MONTH FROM CURRENT_DATE - INTERVAL 2 MONTH) extr UNION SELECT EXTRACT(YEAR_MONTH FROM CURRENT_DATE - INTERVAL 1 MONTH) extr UNION SELECT EXTRACT(YEAR_MONTH FROM CURRENT_DATE - INTERVAL 0 MONTH) extr) dts,
    (SELECT DISTINCT sexnumber FROM sex) sxn) fll LEFT JOIN sex s
ON
  fll.extr = EXTRACT(YEAR_MONTH FROM s.sextime) AND fll.sexnumber=s.sexnumber LEFT JOIN users u
ON
  s.uid = u.uid
GROUP BY
  fll.sexnumber,
  fll.extr
ORDER BY
  fll.sexnumber,
  fll.extr;

在相同的数据集上运行它，您将从MySQL获得以下输出。

+-----------+--------+----------+
| sexnumber | date   | numberOf |
+-----------+--------+----------+
|         1 | 201312 |        1 |
|         1 | 201401 |        2 |
|         1 | 201402 |        2 |
|         1 | 201403 |       25 |
|         2 | 201312 |        0 |
|         2 | 201401 |        1 |
|         2 | 201402 |        2 |
|         2 | 201403 |        1 |
|         3 | 201312 |        0 |
|         3 | 201401 |        0 |
|         3 | 201402 |        1 |
|         3 | 201403 |        0 |
+-----------+--------+----------+
12 rows in set (0.01 sec)

因此，您只需1个查询（而不是3个查询）即可获得所需的内容，而无需处理多余的数组。