[英]Running Sudo Command with paramiko
我正在尝试使用python-paramiko在远程机器上执行sudo命令,当我执行命令时,我将它与3个流绑定,并使用输入流传递密码,但它不起作用,这是回溯结果:
Traceback (most recent call last):
File "<input>", line 1, in <module>
File "/usr/local/lib/python2.7/dist-packages/paramiko/file.py", line 314, in write
self._write_all(data)
File "/usr/local/lib/python2.7/dist-packages/paramiko/file.py", line 439, in _write_all
count = self._write(data)
File "/usr/local/lib/python2.7/dist-packages/paramiko/channel.py", line 1263,in _write
self.channel.sendall(data)
File "/usr/local/lib/python2.7/dist-packages/paramiko/channel.py", line 796, in sendall
raise socket.error('Socket is closed')
error: Socket is closed
这是我的python代码:
import paramiko
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect('192.168.0.104', username='cdc',password='123456')
stdin, stdout, stderr = ssh.exec_command("sudo dmesg")
stdin.write("123456\n")
stdin.flush()
print stdout.readlines()
ssh.close()
有什么帮助吗? 提前致谢
首先,您是否在控制台中尝试使用ssh cdc@192.168.0.104 "sudo -S -p '' dmesg"
。 如果它也失败了,那么您可以检查sshd
设置和sudoer
设置。
如果运行良好,请在行之间添加一些 echo,以便我们可以准确知道何时抛出异常。 我非常怀疑您是否应该将sudo dmesg
更改为sudo -S -p '' dmesg
。
你也可以试试我的 paramiko 包装器。 我可以顺利使用它来访问任何 CentOS/SuSE 节点并执行任何命令(w/wo sudo 权限):
#!/usr/bin/python
from StringIO import StringIO
import paramiko
class SshClient:
"A wrapper of paramiko.SSHClient"
TIMEOUT = 4
def __init__(self, host, port, username, password, key=None, passphrase=None):
self.username = username
self.password = password
self.client = paramiko.SSHClient()
self.client.set_missing_host_key_policy(paramiko.AutoAddPolicy())
if key is not None:
key = paramiko.RSAKey.from_private_key(StringIO(key), password=passphrase)
self.client.connect(host, port, username=username, password=password, pkey=key, timeout=self.TIMEOUT)
def close(self):
if self.client is not None:
self.client.close()
self.client = None
def execute(self, command, sudo=False):
feed_password = False
if sudo and self.username != "root":
command = "sudo -S -p '' %s" % command
feed_password = self.password is not None and len(self.password) > 0
stdin, stdout, stderr = self.client.exec_command(command)
if feed_password:
stdin.write(self.password + "\n")
stdin.flush()
return {'out': stdout.readlines(),
'err': stderr.readlines(),
'retval': stdout.channel.recv_exit_status()}
if __name__ == "__main__":
client = SshClient(host='host', port=22, username='username', password='password')
try:
ret = client.execute('dmesg', sudo=True)
print " ".join(ret["out"]), " E ".join(ret["err"]), ret["retval"]
finally:
client.close()
对不起,我没有时间详细回答,但我能够使用此建议在 paramiko 上实施 sudo 命令
#!/usr/bin/env python
import paramiko
l_password = "yourpassword"
l_host = "yourhost"
l_user = "yourusername"
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect(l_host, username=l_user, password=l_password)
transport = ssh.get_transport()
session = transport.open_session()
session.set_combine_stderr(True)
session.get_pty()
#for testing purposes we want to force sudo to always to ask for password. because of that we use "-k" key
session.exec_command("sudo -k dmesg")
stdin = session.makefile('wb', -1)
stdout = session.makefile('rb', -1)
#you have to check if you really need to send password here
stdin.write(l_password +'\n')
stdin.flush()
for line in stdout.read().splitlines():
print 'host: %s: %s' % (l_host, line)
我知道这个问题有点老了,但我也想同时使用 sudo 和 paramiko。 我花了一段时间才想出这个解决方案。 它可能并不适合所有人,但我认为值得添加。
def ssh_handler(hostname, username=USER, password=PASS, command=CMD):
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect(hostname,
username=username,
password=password)
stdin, stdout, stderr = ssh.exec_command(prepare_command(command))
# stdin.write(password+'\n')
response = stdout.read()
ssh.close()
print response
def prepare_command(command):
if (not isinstance(command, basestring)):
command = ' ; '.join(command)
command = command.replace('"','\"')
command = 'sudo -s -- " '+command+' " \n'
return command
# kind of a dumb example but you get the point
mycmd = [];
mycmd.append('cd /dir/this/user/doesnt/have/access/to')
mycmd.append('ls -las')
mycmd.append('cat file_in_dir.txt')
ssh_handler(server, command=mycmd)
我能够实现在其他 Stackoverflow 线程中找到的这个解决方案。
我的解决方案是在需要使用带有sudo
的命令时使用invoke_shell()
。
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