[英]C++11 atomics: does it make sense, or is it even possible, to use them with memory mapped I/O?
[英]Access Memory Mapped I/O
我对嵌入式系统编程非常陌生,我只需要学习如何通过c ++代码操纵给定的代码即可。
鉴于:
电机1映射到0x60000000
电机2映射到0x50000000
以下是当前32位寄存器的定义
REGISTER NAME | BYTE OFFSET | NOTES
----------------------------------------------------------------------
motor_interrupt 0x00 service interrupts
motor_status 0x01 enable on demand access to status elements
motor_command 0x02 enable command of the motor
REGISTER NAME | NAME | BITS | ACCESS TYPE | DESC
----------------------------------------------------------------------------------
motor_interrupt_register
CLOSED 0 R/W high when motor transitions to CLOSED position
OPEN 1 R/W high when motor transitions to OPEN position
RESERVED 2.31 N/A reserved for future use
motor_status
SPEED 0.2 R speed in counts/seconds
STATE 3 R current state of motor
POSITION 4.13 R current position of the motor
RESERVED 14.31 n/a reserved for future use
我发现很难使用给定的示例代码查看C ++代码,这时我知道我需要访问register_name并将其位设置为执行特定任务,或者读取寄存器名称以获取状态。
我想如果在C ++代码中使用它,我会更加理解。 给定的是一个自动门系统(我没有写按钮的详细信息)。 我需要在c ++中访问register_name或byte_offset吗?
非常感谢您的帮助
读取中断/状态寄存器的C / C ++示例:
volatile uint32_t * const motor1 = (uint32_t *)0x60000000; // base addresses for motors 1 and 2
volatile uint32_t * const motor2 = (uint32_t *)0x50000000;
enum // register offsets from base address
{
motor_interrupt, // 0x00 - service interrupts
motor_status, // 0x01 - enable on demand access to status elements
motor_command // 0x02 - enable command of the motor
}
// read status/interrupt registers
uint32_t current_int_1 = motor1[motor_interrupt];
uint32_t current_int_2 = motor2[motor_interrupt];
uint32_t current_status_1 = motor1[motor_status];
uint32_t current_status_2 = motor2[motor_status];
类似于将32位值写入命令寄存器:
motor1[motor_command] = 0x8000 | (0x12 << 6) | 0x01;
motor2[motor_command] = 0x0;
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