[英]Split a string on multiple characters in python
我试图在python中的多个字符上拆分一个字符串就像我在Java中这样做:
private static final String SPECIAL_CHARACTERS_REGEX = "[ :;'?=()!\\[\\]-]+|(?<=\\d)(?=\\D)";
String rawMessage = "let's meet tomorrow at 9:30p? 7-8pm? i=you go (no Go!) [to do !]";
String[] tokens = rawMessage.split(SPECIAL_CHARACTERS_REGEX);
System.out.println(Arrays.toString(tokens));
我试图在python中完全相同,但是当我这样做时,如果我只是在正则表达式中添加“单引号”字符,它就不会被标记化。 如何从python创建与上面的Java程序相同的结果解析结果?
这个:
import re
tokens = re.split(' \.', line);
print tokens
对于线路:
"let's meet tomorrow at 9:30p? 7-8pm? i=you go (no Go!) [to do !]"
得到:
["let's meet tomorrow at 9:30p? 7-8pm? i=you go (no Go!) [to do !]";]
当我这样做时:
[let, s, meet, tomorrow, at, 9, 30, p, 7, 8, pm, i, you, go, no, Go, to, do]
这是一个找到而不是拆分的替代方案:
>>> s = "let's meet tomorrow at 9:30p? 7-8pm? i=you go (no Go!) [to do !]"
>>> re.findall(r'\d+|[A-Za-z]+', s)
['let', 's', 'meet', 'tomorrow', 'at', '9', '30', 'p', '7', '8', 'pm', 'i', 'you', 'go', 'no', 'Go', 'to', 'do']
如果可以将字母和数字保持在一起,请使用'[0-9A-Za-z]+'
。 对于字母,数字和下划线,请使用r'\\w+'
。
使用您在Java中使用的相同正则表达式:
line = "let's meet tomorrow at 9:30p? 7-8pm? i=you go (no Go!) [to do !]"
tokens = re.split("[ :;'?=()!\\[\\]-]+|(?<=\\d)(?=\\D)", line)
tokens = [token for token in tokens if len(token) != 0] # remove empty strings!
print(tokens)
# ['let', 's', 'meet', 'tomorrow', 'at', '9', '30p', '7', '8pm', 'i', 'you', 'go', 'no', 'Go', 'to', 'do']
使用以下代码
>>> chars = "[:;'?=()!\-]+<" #Characters to remove
>>> sentence = "let's meet tomorrow at 9:30p? 7-8pm? i=you go (no Go!) [to do !]" #Sentence
>>> for k in sentence: #Loops over everything in the sentence
... if k in chars: #Checks if the variable is one we want to remove
... sentence = sentence.replace(k, ' ') #If it is, it replaces it
...
>>> sentence = sentence.replace('p', ' p').replace('pm', ' pm').split() #Adds a space before the 'p' and the 'pm', and then splits it the way we want to
>>> sentence
['let', 's', 'meet', 'tomorrow', 'at', '9', '30', 'p', '7', '8', 'pm', 'i', 'you', 'go', 'no', 'Go', 'to', 'do']
如果你想使用regex
:
line = "let's meet tomorrow at 9:30p? 7-8pm? i=you go (no Go!) [to do !]"
tokens = re.split("[ :;'?=()!\\[\\]-]+|(?<=\\d)(?=\\D)", line)
tokens = [token for token in tokens if len(token) != 0]
tokens = tokens.replace('p', ' p').replace('pm', ' pm').split()
print(tokens)
#['let', 's', 'meet', 'tomorrow', 'at', '9', '30', 'p', '7', '8', 'pm', 'i', 'you', 'go', 'no', 'Go', 'to', 'do']
Java中的分裂正则表达式应该在Python中使用相同的功能。
它可能是一个错误。 混乱可能是重叠
在\\D
和[ :;'?=()!\\[\\]-]
,以及它如何处理(bug~)。
您可以先尝试放置(?<=\\d)(?=\\D)
来解决它,但是它
必须被胁迫才能做到这一点。
这个正则表达式迫使它这样做。 这是一种解决方法吗?
我不知道,没有用python来测试。 但是,它适用于Perl。
强制正则表达式 -
# (?<=\d)(?:[ :;'?=()!\[\]-]+|(?=\D))|(?<!\d|[ :;'?=()!\[\]-])[ :;'?=()!\[\]-]+
(?<= \d )
(?:
[ :;'?=()!\[\]-]+
| (?= \D )
)
|
(?<! \d | [ :;'?=()!\[\]-] )
[ :;'?=()!\[\]-]+
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