如何从数据库中选择比实际数字高的数据

Question

我需要从数据库中选择用户，该用户的得分（时间列）高于10。该怎么做？ 现在，它选择所有用户。

现在我的代码：

    $query = "SELECT userName,min(time) time FROM game group by userName order by time ASC LIMIT 15";
if (!$mysqli->set_charset("utf8")) {
    printf("Error loading character set utf8: %s\n", $mysqli->error);

Answer 1

您可以使用WHERE子句来过滤结果

SELECT userName,min(time) time 
FROM game
WHERE  `time` >10
group by userName 
order by time ASC LIMIT 15

或者，如果您要过滤聚合函数的结果集，则可以使用HAVING子句

SELECT userName,min(time) time 
FROM game
group by userName 
HAVING  min(time) >10
order by time ASC LIMIT 15 

Answer 2

只需添加WHERE子句，例如：

    $query = "SELECT userName,min(time) time FROM game WHERE time>10 group by userName order by time ASC LIMIT 15";
if (!$mysqli->set_charset("utf8")) {
    printf("Error loading character set utf8: %s\n", $mysqli->error);

Answer 3

您需要执行以下操作：

SELECT userName,min(time) time 
FROM game WHERE time > 10 
group by userName 
order by time ASC LIMIT 15;

Answer 4

将HAVING MIN(time) >10到查询中，如下所示：

$query = "SELECT userName, MIN(time) time FROM game GROUP BY username HAVING MIN(time) >10 ORDER BY time ASC LIMIT 15";

您的查询将如下所示：

SELECT userName, MIN(time) time 
FROM game
GROUP BY userName 
HAVING MIN(time) >10
ORDER BY time ASC LIMIT 15