如何從數據庫中選擇比實際數字高的數據

Question

我需要從數據庫中選擇用戶，該用戶的得分（時間列）高於10。該怎么做？ 現在，它選擇所有用戶。

現在我的代碼：

    $query = "SELECT userName,min(time) time FROM game group by userName order by time ASC LIMIT 15";
if (!$mysqli->set_charset("utf8")) {
    printf("Error loading character set utf8: %s\n", $mysqli->error);

Answer 1

您可以使用WHERE子句來過濾結果

SELECT userName,min(time) time 
FROM game
WHERE  `time` >10
group by userName 
order by time ASC LIMIT 15

或者，如果您要過濾聚合函數的結果集，則可以使用HAVING子句

SELECT userName,min(time) time 
FROM game
group by userName 
HAVING  min(time) >10
order by time ASC LIMIT 15 

Answer 2

只需添加WHERE子句，例如：

    $query = "SELECT userName,min(time) time FROM game WHERE time>10 group by userName order by time ASC LIMIT 15";
if (!$mysqli->set_charset("utf8")) {
    printf("Error loading character set utf8: %s\n", $mysqli->error);

Answer 3

您需要執行以下操作：

SELECT userName,min(time) time 
FROM game WHERE time > 10 
group by userName 
order by time ASC LIMIT 15;

Answer 4

將HAVING MIN(time) >10到查詢中，如下所示：

$query = "SELECT userName, MIN(time) time FROM game GROUP BY username HAVING MIN(time) >10 ORDER BY time ASC LIMIT 15";

您的查詢將如下所示：

SELECT userName, MIN(time) time 
FROM game
GROUP BY userName 
HAVING MIN(time) >10
ORDER BY time ASC LIMIT 15