内部联接查询以获取每种武器的结果

Question

我有一个带有内部联接的查询，但是WEAPON是未知的。 我想为每种武器争取最好的杀手。 如何使用此查询执行此操作？ 我对高级查询不是很了解。

    $q = $mysql->query("SELECT `killerID`
            , COUNT(`killerID`) AS tot_kills
            , MIN(`Username`) AS username
            FROM `kills`
            INNER JOIN `players`
            ON `players`.`id` = `kills`.`killerid`
            WHERE `killText` LIKE '%###WEAPON###%'
            GROUP BY `killerID`
            ORDER BY `tot_kills` DESC") or die($mysql->error);

Answer 1

由于使用join ，因此需要在select子句中指定表名。 尝试类似：

SELECT `kills`.`killerID`
            , COUNT(`kills`.`killerID`) AS tot_kills
            , MIN(`players`.`Username`) AS username
            FROM `kills`
            INNER JOIN `players`
            ON `players`.`id` = `kills`.`killerid`
            WHERE `kills`.`killText` LIKE '%###WEAPON###%'
            GROUP BY `kills`.`killerID`
            ORDER BY `kills`.`tot_kills` DESC

Answer 2

我想你应该按武器，而不是杀手ID，只要你想的数killerID的weapon 。

请注意，您不需要所有这些反引号。 仅当查询中的表名或列名是保留字之一时，才需要反引号。

SELECT killerID
        , COUNT(killerID) AS tot_kills
        , MIN(Username) AS username
FROM kills
INNER JOIN players
  ON players.id = kills.killerid
WHERE killText LIKE '%###WEAPON###%'
GROUP BY kills.killText
ORDER BY tot_kills DESC