I have this query with an inner-join, however the WEAPON is unknown. I want to get the best killer for each weapon. How can I do this with this query? I'm not really experienced with advanced queries.
$q = $mysql->query("SELECT `killerID`
, COUNT(`killerID`) AS tot_kills
, MIN(`Username`) AS username
FROM `kills`
INNER JOIN `players`
ON `players`.`id` = `kills`.`killerid`
WHERE `killText` LIKE '%###WEAPON###%'
GROUP BY `killerID`
ORDER BY `tot_kills` DESC") or die($mysql->error);
You need to specify the table names in the select clause since you are using join
. Try something like:
SELECT `kills`.`killerID`
, COUNT(`kills`.`killerID`) AS tot_kills
, MIN(`players`.`Username`) AS username
FROM `kills`
INNER JOIN `players`
ON `players`.`id` = `kills`.`killerid`
WHERE `kills`.`killText` LIKE '%###WEAPON###%'
GROUP BY `kills`.`killerID`
ORDER BY `kills`.`tot_kills` DESC
I think you should group by weapon and not killer id, as you want number of killerID
by weapon
.
Note that you don't need all these backticks. Backticks are required only if your table name or coluumn name in the query is one of the reserved words.
SELECT killerID
, COUNT(killerID) AS tot_kills
, MIN(Username) AS username
FROM kills
INNER JOIN players
ON players.id = kills.killerid
WHERE killText LIKE '%###WEAPON###%'
GROUP BY kills.killText
ORDER BY tot_kills DESC
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