在php中插入mysql时出错
[英]Error while inserting into mysql in php
问题描述
<?php
if (isset($_POST['submitted'])){
include('connect.php');
$name=$_POST['name'];
$addr=$_POST['addr'];
$phno=$_POST['phno'];
$tr=$_POST['tr'];
$trd=$_POST['trd'];
$sname=$_POST['sname'];
$sphno=$_POST['sphno'];
$sfield=$_POST['sfield'];
$med=$_POST['med'];
$apaid=$_POST['apaid'];
$apend=$_POST['apend'];
$sqlinsert="INSERT INTO patient (name , addr , phno , tname , tdate , sName , sphno , sSpeciality , med , amtpaid , amtrem) VALUES
('$name','$addr','$phno','$tr','$trd','$sname','$sphno','$sfield','$med','$apaid','$apend')";
if(!mysql_query($dbcon , $sqlinsert))
{
die('error inserting new record');
}
else
echo "new";
}
?>
<html>
<head>
<title>Insert Data</title>
</head>
<body>
<h1>Insert Data</h1>
<form method="post" action="insert.php">
<input type="hidden" name="submitted" value="true" />
<fieldset>
<legend>New Patient</legend>
<label>Name : <input type="text" name="name" /></label>
<label>Address : <input type="text" name="addr" /></label>
<label>Phone no : <input type="text" name="phno" /></label>
<label>Treatment : <input type="text" name="tr" /></label>
<label>Treatment date : <input type="text" name="trd" /></label>
<label>Specialist Recommended : <input type="text" name="sname" /></label>
<label>Specialist phno : <input type="text" name="sphno" /></label>
<label>Specialist field : <input type="text" name="sfield" /></label>
<label>Medicine : <input type="text" name="med" /></label>
<label>Amount Paid : <input type="text" name="apaid" /></label>
<label>Amount Pending : <input type="text" name="apend" /></label>
</fieldset>
<br />
<input type="submit"value="add new record" />
</form>
</body>
</html>
即使表有一个字符串变量，插入时也会出现此错误
警告：mysql_query（）期望参数1为字符串，在第18行的C：\\ xampp \\ htdocs \\ insert.php中给出的对象错误插入新记录
请帮忙...
3 个解决方案
解决方案1
1
解决方案2
1 2014-04-09 17:53:57
查看本手册。 http://php.net/manual/en/function.mysql-query.php参数1是查询，2是conn
解决方案3
0 2014-04-09 18:03:50
您将mysql连接对象作为参数传递给mysql_query()函数。 mysql_query()只需要1个字符串参数。 使用mysqli_query()你必须改变你的代码..
<?php
if (isset($_POST['submitted'])){
include('connect.php');
$name=$_POST['name'];
$addr=$_POST['addr'];
$phno=$_POST['phno'];
$tr=$_POST['tr'];
$trd=$_POST['trd'];
$sname=$_POST['sname'];
$sphno=$_POST['sphno'];
$sfield=$_POST['sfield'];
$med=$_POST['med'];
$apaid=$_POST['apaid'];
$apend=$_POST['apend'];
$sqlinsert="INSERT INTO patient (name , addr , phno , tname , tdate , sName , sphno , sSpeciality , med , amtpaid , amtrem) VALUES
('$name','$addr','$phno','$tr','$trd','$sname','$sphno','$sfield','$med','$apaid','$apend')";
if(!mysqli_query($dbcon , $sqlinsert))
{
die('error inserting new record');
}
else
echo "new";
}
？>
使用 MySQL 和 PHP 将数据插入数据库时出现 SQL 错误
[英]Getting SQL error while inserting the data into database using MySQL and PHP
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.