Error while inserting into mysql in php
Question
<?php
if (isset($_POST['submitted'])){
include('connect.php');
$name=$_POST['name'];
$addr=$_POST['addr'];
$phno=$_POST['phno'];
$tr=$_POST['tr'];
$trd=$_POST['trd'];
$sname=$_POST['sname'];
$sphno=$_POST['sphno'];
$sfield=$_POST['sfield'];
$med=$_POST['med'];
$apaid=$_POST['apaid'];
$apend=$_POST['apend'];
$sqlinsert="INSERT INTO patient (name , addr , phno , tname , tdate , sName , sphno , sSpeciality , med , amtpaid , amtrem) VALUES
('$name','$addr','$phno','$tr','$trd','$sname','$sphno','$sfield','$med','$apaid','$apend')";
if(!mysql_query($dbcon , $sqlinsert))
{
die('error inserting new record');
}
else
echo "new";
}
?>
<html>
<head>
<title>Insert Data</title>
</head>
<body>
<h1>Insert Data</h1>
<form method="post" action="insert.php">
<input type="hidden" name="submitted" value="true" />
<fieldset>
<legend>New Patient</legend>
<label>Name : <input type="text" name="name" /></label>
<label>Address : <input type="text" name="addr" /></label>
<label>Phone no : <input type="text" name="phno" /></label>
<label>Treatment : <input type="text" name="tr" /></label>
<label>Treatment date : <input type="text" name="trd" /></label>
<label>Specialist Recommended : <input type="text" name="sname" /></label>
<label>Specialist phno : <input type="text" name="sphno" /></label>
<label>Specialist field : <input type="text" name="sfield" /></label>
<label>Medicine : <input type="text" name="med" /></label>
<label>Amount Paid : <input type="text" name="apaid" /></label>
<label>Amount Pending : <input type="text" name="apend" /></label>
</fieldset>
<br />
<input type="submit"value="add new record" />
</form>
</body>
</html>
im getting this error while inserting even when the table has a string variable
Warning: mysql_query() expects parameter 1 to be string, object given in C:\\xampp\\htdocs\\insert.php on line 18 error inserting new record
please help...
3 answers
solution1
1
Read the docs :
mixed mysql_query ( string $query [, resource $link_identifier = NULL ] )
Side point:
There is no more support for
mysql_*functions, they are officially deprecated , no longer maintained and will be removed in the future. You should update your code with PDO or MySQLi to ensure the functionality of your project in the future.
solution2
1 2014-04-09 17:53:57
check this manual. http://php.net/manual/en/function.mysql-query.php Parameter 1 is query and 2 is conn
solution3
0 2014-04-09 18:03:50
you are passing mysql connection object as argument to mysql_query() function . mysql_query() expects only 1 string parameter . use mysqli_query() you have to change your code ..
<?php
if (isset($_POST['submitted'])){
include('connect.php');
$name=$_POST['name'];
$addr=$_POST['addr'];
$phno=$_POST['phno'];
$tr=$_POST['tr'];
$trd=$_POST['trd'];
$sname=$_POST['sname'];
$sphno=$_POST['sphno'];
$sfield=$_POST['sfield'];
$med=$_POST['med'];
$apaid=$_POST['apaid'];
$apend=$_POST['apend'];
$sqlinsert="INSERT INTO patient (name , addr , phno , tname , tdate , sName , sphno , sSpeciality , med , amtpaid , amtrem) VALUES
('$name','$addr','$phno','$tr','$trd','$sname','$sphno','$sfield','$med','$apaid','$apend')";
if(!mysqli_query($dbcon , $sqlinsert))
{
die('error inserting new record');
}
else
echo "new";
}
?>
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