[英]cannot bind 'std::basic_istream<char>' lvalue to 'std::basic_istream<char>&&'
我有这个c ++代码片段在visual studio中工作正常，但在gcc中出错。 欢迎任何有关如何使其工作的建议？
template <typename ConvertType>
inline bool Parse(const std::string& input, ConvertType& output)
{
std::stringstream stream(input);
stream.imbue(std::locale::classic());
return (stream >> output) != NULL;
}
我收到此错误：
./Configuration/Option.h:32:38: error: cannot bind 'std::basic_istream' lvalue to 'std::basic_istream&&' /usr/include/c++/4.6/istream:852:5: error: initializing argument 1 of 'std::basic_istream& std::operator>>(std::basic_istream&&, _Tp&) [with _CharT = char, _Traits = std::char_traits, _Tp = Color]'
(stream >> output)返回(stream >> output)的引用，无法与NULL进行比较。 你可以简单地回来
return (stream >> output);
它将通过调用operator void*() const （C ++ 11中的explicit operator bool() const fail()来测试流，它调用fail()函数来测试操作是否成功。
重载运算符>>：无法绑定'std::basic_istream<char> ' 左值到 'std::basic_istream<char> &&'
[英]Overloading operator>>: cannot bind ‘std::basic_istream<char>’ lvalue to ‘std::basic_istream<char>&&’
make 失败并出现错误“无法转换 'std::istream {aka std::basic_istream<char> }' 到 'bool' 作为回报”
[英]make fails with error “cannot convert ‘std::istream {aka std::basic_istream<char>}’ to ‘bool’ in return”
错误：与“ operator >>”不匹配（操作数类型为“ std :: istream {aka std :: basic_istream <char> }和'std :: vector <double> '）
[英]Error: no match for 'operator>>' (operand types are 'std::istream {aka std::basic_istream<char>}' and 'std::vector<double>')
错误：'operator>>' 不匹配（操作数类型是 'std::istream' {aka 'std::basic_istream<char> '} 和 'const int')|</char>
[英]error: no match for 'operator>>' (operand types are 'std::istream' {aka 'std::basic_istream<char>'} and 'const int')|
无法编译 TRAP 库：'operator:=' 不匹配（操作数类型为 'std::basic_istream<char> ' 和 'long int')</char>
[英]Cannot compile TRAP library: no match for ‘operator!=’ (operand types are ‘std::basic_istream<char>’ and ‘long int’)
我收到错误消息：std :: basic_istream没有合适的转换函数 <char, std::char_traits<char> >到char存在
[英]I'm getting the error: no suitable conversion function from std::basic_istream<char, std::char_traits<char>> to char exists
如何安全地序列化std :: basic_istream <char> :: pos_type？
[英]How one can safely serialize std::basic_istream<char>::pos_type?
错误：“ operator >>”不匹配（操作数类型为“ std :: basic_istream” <char> cin >>薪金>> endl; ^
[英]error: no match for 'operator>>' (operand types are 'std::basic_istream<char> cin>> salary >> endl; ^
出于某种原因，我不断收到此错误：“运算符>>”不匹配（操作数类型为“std::istream”{又名“std::basic_istream”<char> '}
[英]for some reason I keep getting this error: no match for 'operator>>' (operand types are 'std::istream' {aka 'std::basic_istream<char>'}
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.