[英]I'm getting the error: no suitable conversion function from std::basic_istream<char, std::char_traits<char>> to char exists
我试图使运算符>>重载，但我想从输入中读取每个字符，但出现错误。 这是代码：
istream& operator>>(istream& input, Natural_Big_Number number)
{
int x;
input >> x;
number.set_nr_digits(x);
char c;
while ((c = input.get(c)))
{
}
}
如果您希望它返回字符，则无需为.get()指定参数。 https://en.cppreference.com/w/cpp/io/basic_istream/get
#include <iostream>
using namespace std;
istream& operator>>(istream& input, int number)
{
char c;
while ((c = input.get()))
{
}
}
如果要检查流的布尔值是否false ，则可以执行注释中提到的操作，而不是：
while (input.get(c))
它将字符存储在c然后检查返回的输入流的bool值。
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