如何仅将搜索到的单词作为结果python regex

Question

如何只获取与python中的正则表达式匹配的单词？ 因为我尝试的所有操作也会在找到该字符串的地方打印完整的一行。

正则表达式如下：

\b([1-9][0-9]{1,2})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\/([0-9]{1,2})\b

它匹配IP + CIDR（例如12.0.0.0/8）

我在其中搜索的文本如下：

04/30","172.18.186.0/24","172.18.185.0/24","172.18.177.16/28","dwefwf-1.RI-nc_wefwfwefwefpat_intweb_fe","172.18.176.16/28","edefwfwf
t_pat_infwef_fe","172.18.178.16/28","dwefwefwef-wefwffwefwefwef_dr_efwefeb_fe","172.18.176.80/28","DSwefwfH2. 
RI-nc_rat_dr_fweweb_fe","172.18.178.48/28","172.18.177.208/28","wefwef 
wefwtfweapp_fe","172.18.176.208/28","wfwfwefwefwefH2.RI-nwefwefdr_app_fe","172.18.177.192/28","de1dfwwf-1.wefewf","172.18.176.1
92/28","

Answer 1

您应按以下方式修改regex ：

\\b(([1-9][0-9]{1,2})\\.([0-9]{1,3})\\.([0-9]{1,3})\\.([0-9]{1,3})\\/([0-9]{1,2}))\\b

然后提取第一个匹配的组： \\1

演示： http : //repl.it/R0W/1 （需要一段时间才能运行）

Answer 2

我认为您的正则表达式可以正常工作。 如果要获取匹配的字符串，请使用group函数。 像这样：

import re

regexp = r'\b([1-9][0-9]{1,2})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\/([0-9]{1,2})\b'

text = '''04/30","172.18.186.0/24","172.18.185.0/24","172.18.177.16/28","dwefwf-1.RI-nc_wefwfwefwefpat_intweb_fe","172.18.176.16/28","edefwfwf
t_pat_infwef_fe","172.18.178.16/28","dwefwefwef-wefwffwefwefwef_dr_efwefeb_fe","172.18.176.80/28","DSwefwfH2. 
RI-nc_rat_dr_fweweb_fe","172.18.178.48/28","172.18.177.208/28","wefwef 
wefwtfweapp_fe","172.18.176.208/28","wfwfwefwefwefH2.RI-nwefwefdr_app_fe","172.18.177.192/28","de1dfwwf-1.wefewf","172.18.176.1
92/28","'''

for i in re.finditer(regexp, text):
    print i.group(0)