在sed反向引用替换中转义双引号

Question

我有以下文字：

Matt has 11 eggs and they are brown
Helen has 23 ducks and they are black and brown
Todd has 34 quarters and they are silver
Bud has 45 pens and they are red, yellow, "greenish" and blue

当我运行以下sed命令时：

sed -E "s/([^ ]+) has ([^ ]+) ([^ ]+) and they are (.*)/\"\1\",\"\2\",\"\3\",\"\4\"/" input

我收到此CSV：

"Matt","11","eggs","brown"
"Helen","23","ducks","black and brown"
"Todd","34","quarters","silver"
"Bud","45","pens","red, yellow, "greenish" and blue"

但是我真正想要的是这个（引号正确转义）：

"Matt","11","eggs","brown"
"Helen","23","ducks","black and brown"
"Todd","34","quarters","silver"
"Bud","45","pens","red, yellow, \"greenish\" and blue"

我该怎么做？

Answer 1

尝试：

sed -E 's/"/\\"/g; 
  s/([^ ]+) has ([^ ]+) ([^ ]+) and they are (.*)/"\1","\2","\3","\4"/' input

这首先将所有"实例替换为\\" ，然后执行原始命令。 请注意，在sed程序周围使用单引号会使它更具可读性。

Answer 2

这可能对您有用（GNU sed）：

sed -r 's/"/\\&/g;s/^\\"|\\(",)\\"|\\"$/\1"/g'  file

转换所有"的，以\\"的，然后删除\\从那些在起点，终点和插图中的。