[英]copy cell style openpyxl
我试图将工作表default_sheet
复制到同一工作簿中的新工作表new_sheet
。
我设法创建了一个新工作表并从默认工作表复制值。 如何将每个单元格的样式复制到new_sheet单元格中?
new_sheet = workbook.create_sheet()
new_sheet.title = sheetName
default_sheet = workbook.get_sheet_by_name('default')
new_sheet = workbook.get_sheet_by_name(sheetName)
for row in default_sheet.rows:
col_idx = float(default_sheet.get_highest_column())
starting_col = chr(65 + int(col_idx))
for row in default_sheet.rows:
for cell in row:
new_sheet[cell.get_coordinate()] = cell.value
<copy also style of each cell>
我目前正在使用openpyxl 1.8.2,但我想切换到1.8.5。
一个解决方案是复制:
from copy import copy, deepcopy
new_sheet._styles[cell.get_coordinate()] = copy(
default_sheet._styles[cell.get_coordinate()])
从openpyxl 2.5.4开始,python 3.4 :(对下面的旧版本进行细微更改)
new_sheet = workbook.create_sheet(sheetName)
default_sheet = workbook['default']
from copy import copy
for row in default_sheet.rows:
for cell in row:
new_cell = new_sheet.cell(row=cell.row, column=cell.col_idx,
value= cell.value)
if cell.has_style:
new_cell.font = copy(cell.font)
new_cell.border = copy(cell.border)
new_cell.fill = copy(cell.fill)
new_cell.number_format = copy(cell.number_format)
new_cell.protection = copy(cell.protection)
new_cell.alignment = copy(cell.alignment)
对于openpyxl 2.1
new_sheet = workbook.create_sheet(sheetName)
default_sheet = workbook['default']
for row in default_sheet.rows:
for cell in row:
new_cell = new_sheet.cell(row=cell.row_idx,
col=cell.col_idx, value= cell.value)
if cell.has_style:
new_cell.font = cell.font
new_cell.border = cell.border
new_cell.fill = cell.fill
new_cell.number_format = cell.number_format
new_cell.protection = cell.protection
new_cell.alignment = cell.alignment
StyleableObject
实现将样式存储在单个列表中,单元格上的_style
和样式属性实际上是此数组的getter和setter。 你可以单独为每个样式实现副本,但这会很慢,特别是如果你像我一样在繁忙的内循环中进行。
如果您愿意深入了解私有类属性,则可以更快速地克隆样式:
if cell.has_style:
new_cell._style = copy(cell._style)
FWIW这是优化的WorksheetCopy
类在_copy_cells
方法中_copy_cells
方式。
可能这是大多数人的便捷方式。
from openpyxl import load_workbook
from openpyxl import Workbook
read_from = load_workbook('path/to/file.xlsx')
read_sheet = read_from.active
write_to = Workbook()
write_sheet = write_to.active
write_sheet['A1'] = read_sheet['A1'].value
write_sheet['A1'].style = read_sheet['A1'].style
write_to.save('save/to/file.xlsx')
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