[英]Why isn't the action for my newly created UISwitch being called (Objective-c, Xcode 7.0.1)?
[英]why isn't my DEBUG preprocessor macro being recognized objective-c
我接手了一个有几个构建方案的项目:演示,发布,调试和生产。 整个代码..有几个预处理器宏if语句即
#ifdef DEMO
static NSString *const URL_SMART_TAXI = @"http://demo.theapp.com";
#elif PRODUCTION
static NSString *const URL_SMART_TAXI = @"http://prod.theapp.com";
#elif DEBUG
static NSString *const URL_SMART_TAXI = @"http://localhost:8000";
#else
static NSString *const URL_SMART_TAXI = @"http://dev.theapp.com";
#endif
出于某种原因,当我使用演示方案或生产方案构建时,这总是有效...但它只是不适用于调试 (每当我更改方案并运行调试时...它总是跳过调试并且去对于外卡选项)..
我看了整个项目,我没有看到任何针对演示或生产的特殊处理没有给出调试。
如果我运行grep -nri %environment% *
这就是结果:
grep -nri production *
project.pbxproj:2767: 84380FEB1705D3E40085487D /* Production */ = {
project.pbxproj:2797: name = Production;
project.pbxproj:2799: 84380FEC1705D3E40085487D /* Production */ = {
project.pbxproj:2832: "-DPRODUCTION",
project.pbxproj:2846: name = Production;
project.pbxproj:3013: 84380FEB1705D3E40085487D /* Production */,
project.pbxproj:3024: 84380FEC1705D3E40085487D /* Production */,
xcshareddata/xcschemes/theApp.xcscheme:47: buildConfiguration = "Production"
grep -nri demo *
project.pbxproj:2685: 6314932116E4F7D000B351CA /* Demo */ = {
project.pbxproj:2715: name = Demo;
project.pbxproj:2717: 6314932216E4F7D000B351CA /* Demo */ = {
project.pbxproj:2751: "-DDEMO",
project.pbxproj:2765: name = Demo;
project.pbxproj:3012: 6314932116E4F7D000B351CA /* Demo */,
project.pbxproj:3023: 6314932216E4F7D000B351CA /* Demo */,
xcshareddata/xcschemes/theApp.xcscheme:87: buildConfiguration = "Demo"
grep -nri debug *
project.pbxproj:2848: 847D410E168CBD3700CE1B96 /* Debug */ = {
project.pbxproj:2863: "DEBUG=1",
project.pbxproj:2879: name = Debug;
project.pbxproj:2912: 847D4111168CBD3700CE1B96 /* Debug */ = {
project.pbxproj:2955: name = Debug;
project.pbxproj:2972: "DEBUG=1",
project.pbxproj:3010: 847D410E168CBD3700CE1B96 /* Debug */,
project.pbxproj:3021: 847D4111168CBD3700CE1B96 /* Debug */,
xcshareddata/xcschemes/theApp.xcscheme:26: selectedDebuggerIdentifier = "Xcode.DebuggerFoundation.Debugger.LLDB"
xcshareddata/xcschemes/theApp.xcscheme:27: selectedLauncherIdentifier = "Xcode.DebuggerFoundation.Launcher.LLDB"
xcshareddata/xcschemes/theApp.xcscheme:29: buildConfiguration = "Debug">
xcshareddata/xcschemes/theApp.xcscheme:43: selectedDebuggerIdentifier = "Xcode.DebuggerFoundation.Debugger.LLDB"
xcshareddata/xcschemes/theApp.xcscheme:44: selectedLauncherIdentifier = "Xcode.DebuggerFoundation.Launcher.LLDB"
xcshareddata/xcschemes/theApp.xcscheme:49: debugDocumentVersioning = "YES"
xcshareddata/xcschemes/theApp.xcscheme:72: debugDocumentVersioning = "YES">
xcshareddata/xcschemes/theApp.xcscheme:84: buildConfiguration = "Debug">
有任何想法吗?
更新: +构建设置的相关部分
这是因为你在做“ #elif
”,这是不一样的东西“ #elifdef
”(如果这样的事情存在)。
您应该同时定义PRODUCTION,DEBUG和DEMO,但只将一个设置为“ 1
”,将其他设置为“ 0
”。
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